java.sql.SQLException : Data truncated for column 'gender' at row 1 for enum

Question

我正在使用注释将记录保存在 MySQL 数据库中。

在数据库端，我将列性别定义为性别ENUM('M','F')

定义枚举如下:

public enum Gender {
M,F;
}

在注释类中，我定义枚举属性如下:

@Column(name="gender")
@Enumerated(EnumType.ORDINAL) 
private Enum<Gender> gender=Gender.M;

我将属性保存在数据库中，如下所示:

employee.setGender(Gender.M);

但是当我运行程序时出现以下错误:

Hibernate: insert into Employees (birth_date, first_name,gender,hire_date,last_nane values
org.hibernate.exception.GenericJDBCException: Data truncated for column 'gender' at row 1
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert         
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:110)
at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation    
at org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke
at com.sun.proxy.$Proxy11.executeUpdate(Unknown Source)
at org.hibernate.id.IdentityGenerator$GetGeneratedKeysDelegate.executeAndExtract   
at org.hibernate.id.insert.AbstractReturningDelegate.performInsert
at org.hibernate.persister.entity.AbstractEntityPersister.insert
at org.hibernate.persister.entity.AbstractEntityPersister.insert  
at org.hibernate.action.internal.EntityIdentityInsertAction.execute
at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:362)
at org.hibernate.engine.spi.ActionQueue.addResolvedEntityInsertAction(ActionQueue.java:203)
at org.hibernate.engine.spi.ActionQueue.addInsertAction(ActionQueue.java:183)
at org.hibernate.engine.spi.ActionQueue.addAction(ActionQueue.java:167)

at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1073)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3609)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3541)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2002)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2163)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2624)
at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2127)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2427)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2345)
at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2330)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation
... 25 more

我尝试使用字符串和序数，但错误仍然存​​在。

Ordinal 表示 int。我是否需要将性别类型的架构定义从 enum 更改为 String 或 int。 Hibernate 注释不适用于列类型枚举吗？ 请帮助我解决这个问题。

Answer 1

什么Enum<Gender> ？ Gender已经是Enum而这种类型的声明不是您想要的。
尝试更简单的:

@Column(name="gender")
@Enumerated(EnumType.ORDINAL) 
private Gender gender=Gender.M;