java - Simplexml 列表不起作用

Question

我想使用 SimpleXML 读取并解析包含员工信息的 XML 文件。框架。这是我的 XML 文件:

<?xml version="1.0" encoding="UTF-8"?>
    <Employees>
        <Employee>
            <age>29</age>
            <name>Pankaj</name>
            <gender>Male</gender>
            <role>Java Developer</role>
        </Employee>
        <Employee>
            <age>35</age>
            <name>Lisa</name>
            <gender>Female</gender>
            <role>CEO</role>
        </Employee>
    </Employees>

这是员工类:

@Root
public class Employees {

    @ElementList(inline = true)
    private List<Employee> list;

    public List<Employee> getList() {
        return list;
    }
}

这是 Employee 类:

@Root
public class Employee {

    @Element
    private String name;

    @Element
    private String gender;

    @Element
    private int age;

    @Element
    private String role;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getGender() {
        return gender;
    }

    public void setGender(String gender) {
        this.gender = gender;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }

    public String getRole() {
        return role;
    }

    public void setRole(String role) {
        this.role = role;
    }

    @Override
    public String toString() {
        return " Name=" + this.name + " Age="
                + this.age + " Gender=" + this.gender + " Role=" + this.role;
    }
}

但是当我尝试读取和解析 XML 文件时，发生了异常。这是输出:

Exception in thread "main" org.simpleframework.xml.core.ElementException: Element 'Employee' does not have a match in class Employees at line 3

Answer 1

您在定义列表名称时犯了错误:

@Root
public class Employees {

    @ElementList(inline = true)
    private List<Employee> Employees; //The list name should match with xml list name."

    public List<Employee> getList() {
        return list;
    }
}

在您的 XML 中，您有一个“Employees”元素类型“Employee”列表。但是在你的java程序中，你将“Employees”列表定义为“list”: