我需要制作一个应用程序来计算已经有多少个工作日。例如,2014 年 9 月 23 日。这是本月的第 17 个工作日。显然它不包括周末。当该月结束时,计数器将重新开始。因此,当日期为 10 月 1 日时,计数器将等于 1。
我已经有了这组代码,它在今天(2014 年 11 月 24 日)正确工作。输出是 17,这是正确的。但对于其他日期来说,这是错误的。我没有进行一些验证,例如周末检查,因为我正在测试逻辑。
这是代码块:
Date dateToday = new Date();
Calendar cal = Calendar.getInstance();
cal.setTime(dateToday);
int year = cal.get(Calendar.YEAR);
int month = cal.get(Calendar.MONTH);
int day = cal.get(Calendar.DAY_OF_WEEK);
int week = cal.get(Calendar.WEEK_OF_MONTH);
int dayNo=0;
System.out.println("year= " + year + " month= " + month + " day= "
+ day + " week= " + week);
if ((day == Calendar.SATURDAY) && (day == Calendar.SUNDAY)) {
willPush = false;
}else{
if(week>4){
week-=1;
}
if(week==1){
dayNo+=day-1;
}else if(week==2){
dayNo=day+5;
}else if(week==3){
dayNo=day+10;
}else if(week==4){
dayNo=day+15;
}else if(week==5){
dayNo=day+20;
}
dayNo-=1;
}
System.out.println("DayNO: "+dayNo);
更新:刚刚发现这个逻辑有缺陷,非常有缺陷。将尝试一种新方法,我正在考虑循环查看该月中的几天,然后检查它们是否是周末。但不确定这是否是最好的主意。
最佳答案
这是示例代码。使用joda图书馆。
import org.joda.time.DateTimeConstants;
import org.joda.time.LocalDate;
public class WeekDays {
public static void main(String[] args) {
final LocalDate start = new LocalDate(2014, 1, 1);
final LocalDate end = new LocalDate(2014, 1, 14);
LocalDate weekday = start;
if (start.getDayOfWeek() == DateTimeConstants.SATURDAY ||
start.getDayOfWeek() == DateTimeConstants.SUNDAY) {
weekday = weekday.plusWeeks(1).withDayOfWeek(DateTimeConstants.MONDAY);
}
int weekdayCount = 1;
while (weekday.isBefore(end)) {
weekdayCount++;
System.out.println(weekday);
if (weekday.getDayOfWeek() == DateTimeConstants.FRIDAY)
weekday = weekday.plusDays(3);
else
weekday = weekday.plusDays(1);
}
System.out.println(weekdayCount);
}
}
关于java - 使用日期参数计算工作日,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27100733/