java - 将数组名称作为类方法中的参数传递

Question

// My code is doing something; difficult to get.. still a concept can be grasped.
//I am having my method (searchCity) in class graph.   this method is called from main 
//class and is   yes...  selecting one array  by charachter it is passed with 
public class graph {
	int a = 1000;
	int flag = 0;
	//array of all cities having elements as connection to other cities

	public graph(){
		char [] i =  {'i','v'};
		char [] v =  {'v','u'};
		char [] u =  {'u','b','h'};
		char [] b =  {'b','p','f','u'};
		char [] h =  {'h','u','e'};
		char [] e =  {'e','h'};
		char [] p =  {'p','b','r','c'};
		char [] c =  {'c','p'};
		char [] r =  {'r','s','p'};
		char [] s =  {'s','f','r'};
		char [] f =  {'f','s','b'};
	}
	
	public void searchCity( char i, char j){
		// check for equal array as parameter i (include must )
		for (int z = 0 ; z < i.length; z ++) {
		    if (i[z] == 'j') {
	int ascii = (int) 'j';
 int flag = 1; 
	System.out.println(ascii);

		    }
		    else {
		    	// checking for smallest cost in the complete array
		        int ascii = (int) i[z];
		        if(a>ascii)
		        	a=ascii;
		        else continue;
		    }
		}
		if (flag==0){
			char b = (char) a;
			char [] c = {'b'}; 
		}
		searchCity(c, j);
			}
	

我有一个类，其中有许多以字母命名的数组，如 char [] a、char [] b 等。我在类中还有一个方法。 在主类中，我创建了一个对象，如果我需要传递两个字母，这将类似于仅调用那些传递名称的数组的引用。 就像我在主类中的代码行如下: 对象.函数(char1, char2); 这些字符将是字母表(a，b，c等)可以做到吗？如何 ？？请帮忙。我搜索了它，但确切的问题没有得到解答。问候

Answer 1

如果您询问如何将字符数组传递给函数，您所需要做的就是按如下方式设置函数:

public static void MyFunction(char[] a, char[] b) {
    //do stuff to char arrays
}

然后，当您调用该函数时，您将能够将它们传递给:

char[] a = {'a', 'b', 'c'};
char[] b = {'d', 'e', 'f'};
MyObject.MyFunction(a, b);

如果您发布当前的代码，那将会很有帮助，这样我就可以准确地告诉您您想要做什么。

编辑:

如果您希望能够使用字符调用数组，我建议将它们包含在 HashMap 中:

Map<Character, Character[]> graph = new HashMap<Character, Character[]>();
graph.put('i', new Character[] {'i', 'v'});
graph.put('v', new Character[] {'v', 'u'});
graph.put('u', new Character[] {'u', 'b', 'h'});
// etc.

然后您可以按如下方式调用数组:

System.out.println(graph.get('i')[0]); // Prints 'i'
System.out.println(graph.get('i')[1]); // Prints 'v'
System.out.println(graph.get('i').length); // Prints '2'

所以函数可能是这样的:

public static void MyFunction(char a, char b) {
    graph.get(a)[0]; // grab first character in array
    for (int i=0; i<graph.get(b).length; i++) { 
        // recursively go through array with graph.get(b)[i]
    }
}

Demonstration Here

希望这有帮助。