我最近开发了一个程序，询问用户的年龄:年、月和日。
收到输入后，它必须计算并打印
a) 年龄(以秒为单位)(totalAgeInSecs) 和
b) 剩余生存秒数。 b 将基于平均生命周期(以秒为单位)(avgLifeSpan = 250000000000l。因此，secondsLeft = avgLifeSpan -totalAgeInSecs)。
我知道有一些类和数组可以与循环结合使用，但为了简单性和逻辑理解，我没有使用它们来理解这个项目的“英语”基本原理和逻辑。哈哈。
无论如何，请检查下面的代码，并让我知道您对如何简化重复行或解决此问题的更好方法的想法。谢谢。
import java.util.*;
public class AgeInSeconds {
static Scanner kbd = new Scanner(System.in);
public static void main(String[] args) {
int totalNumDays, daysInMonth, daysToHours;
int yrsToDays,minsInHr, secsInMin;
long timeRemaining, avgLifeSecs;
System.out.println("Enter your age in years months and days: ");
System.out.print("Years: ");
int years = kbd.nextInt();
System.out.print("Months: ");
int months = kbd.nextInt();
System.out.print("Days: ");
int days = kbd.nextInt();
yrsToDays = years * 365;
avgLifeSecs = 2500000000l;
switch (months){
case 1:
daysInMonth = 31;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 2:
daysInMonth = 59;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 3:
daysInMonth = 90;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 4:
daysInMonth = 120;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 5:
daysInMonth = 151;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 6:
daysInMonth = 181;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 7:
daysInMonth = 212;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 8:
daysInMonth = 243;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 9:
daysInMonth = 273;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 10:
daysInMonth = 304;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 11:
daysInMonth = 334;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
break;
case 12:
daysInMonth = 365;
totalNumDays = yrsToDays + daysInMonth + days;
daysToHours = totalNumDays * 24;
minsInHr = daysToHours * 60;
secsInMin = minsInHr * 60;
timeRemaining = avgLifeSecs - secsInMin;
System.out.printf("You have been alive for %,d seconds.\n", secsInMin);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
default:
}
kbd.close();
}
}
这是以下情况下的输出:年 = 24，月 = 5，天 = 8。
Enter your age in years months and days:
Years: 24
Months: 5
Days: 8
You have been alive for 770,601,600 seconds.
The average human life is 2,500,000,000 seconds.
You have 1,729,398,400 seconds.
最佳答案
要正确计算用户的存活天数，您应该首先根据提供的数据和今天的日期计算他的出生日期。例如:
- 用户出生 1 个月，当前日期为 2015 年 9 月 28 日，因此用户出生于 2015 年 8 月 28 日，年龄为 31 天。
- 用户出生 1 个月，当前日期为 2015 年 3 月 2 日，因此用户出生于 2015 年 2 月 2 日，年龄为 28 天。
之后您可以计算以秒为单位的差异。 Java API 中有现成的类和方法来执行这些步骤。最简单的是使用 Java 8 Time API:
import java.time.LocalDateTime;
import java.time.Period;
import java.time.temporal.ChronoUnit;
import java.util.Scanner;
public class AgeInSeconds {
public static void main(String[] args) {
try (Scanner kbd = new Scanner(System.in)) {
System.out.println("Enter your age in years months and days: ");
System.out.print("Years: ");
int years = kbd.nextInt();
System.out.print("Months: ");
int months = kbd.nextInt();
System.out.print("Days: ");
int days = kbd.nextInt();
Period period = Period.of(years, months, days);
LocalDateTime now = LocalDateTime.now();
LocalDateTime birthDate = now.minus(period);
long seconds = birthDate.until(now, ChronoUnit.SECONDS);
long avgLifeSecs = 2500000000l;
long timeRemaining = avgLifeSecs - seconds;
System.out.printf("You have been alive for %,d seconds.\n", seconds);
System.out.printf("The average human life is %,d seconds.\n", avgLifeSecs);
System.out.printf("You have %,d seconds.\n", timeRemaining);
}
}
}
我在这里不讨论统计问题。要计算估计剩余生命周期(假设我是普通人)，您应该对比我年纪大的人的生命周期进行平均。
关于java - switch 语句的效率，Java，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32818139/