java - 面板不会显示在窗口中

Question

我试图在选择 jcheckbox 帽子且矩形可见的情况下启动程序，然后当取消选择复选框时矩形消失，并在再次选择复选框时重新绘制。当我运行程序并选中该框时，另一个复选框会出现在框架左侧。

import java.awt.Color;
import java.awt.Graphics;
import java.awt.event.ItemEvent;
import java.awt.event.ItemListener;
import javax.swing.*;

public class Head extends JPanel {

JCheckBox hat;

public Head() {
    hat = new JCheckBox("Hat");
    hat.setSelected(true);
    hat.addItemListener(new CheckSelection());

    add(hat);
}

class CheckSelection implements ItemListener {

    public void itemStateChanged(ItemEvent ie) {
        repaint();
    }
}


public void paintComponent(Graphics g) {

    setForeground(Color.RED);
    g.drawOval(110, 100, 100, 100);
    g.drawOval(130, 120, 20, 15);
    g.drawOval(170, 120, 20, 15);
    g.drawLine(160, 130, 160, 160);
    g.drawOval(140, 170, 40, 15);
    if (hat.isSelected()) {
        g.drawRect(100, 90, 120, 10);
    }
    }


 public static void main(String[] args) {
    Head head = new Head();
    JFrame f = new JFrame();
    f.add(head);
    f.setSize(400, 400);
    //f.setLayout(null);  
    f.setVisible(true);
    f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
}

}

Answer 1

您没有调用 paintComponent 的 super 方法，从而破坏了绘制链

@Override
protected void paintComponent(Graphics g) {
    super.paintComponent(g);
    setForeground(Color.RED);
    g.drawOval(110, 100, 100, 100);
    g.drawOval(130, 120, 20, 15);
    g.drawOval(170, 120, 20, 15);
    g.drawLine(160, 130, 160, 160);
    g.drawOval(140, 170, 40, 15);
    if (hat.isSelected()) {
        g.drawRect(100, 90, 120, 10);
    } else {
        setForeground(Color.RED);
        g.drawOval(110, 100, 100, 100);
        g.drawOval(130, 120, 20, 15);
        g.drawOval(170, 120, 20, 15);
        g.drawLine(160, 130, 160, 160);
        g.drawOval(140, 170, 40, 15);
    }
}

Graphics 上下文是组件之间的共享资源，paintComponent 的工作之一是准备用于绘制的 Graphics，通常通过用组件的背景颜色填充它。因此，未能调用 super.paintComponent 意味着之前绘制到 Graphics 上下文中的内容仍将存在

参见Painting in AWT and Swing和 Performing Custom Painting有关 Swing 中绘画工作原理的更多详细信息