我有 LString 类,它模仿标准 Java String 和 StringBuilder 类。我在开始实现替换方法以将子字符串“LString”的字符替换为“lStr”中的字符时遇到问题。我的替换方法位于代码底部。
如果 If start == end,则给出特殊情况,这会在 LString 中的给定位置插入“lStr”。如果 start == end == this.length(),则将 lStr 附加到此 LString 的末尾。
public class LString {
node front;
int length;
LString next;
// create node class
public class node {
char data;
node next;
public node(char newData) {
data = newData;
}
public node(char newData, node newNext) {
data = newData;
next = newNext;
}
}
// LString constructor
// constructs LString object representing empty list of chars
public LString(){
this.length = 0;
this.front = null;
}
// Construct LString copy of original parameter
public LString(String original){
//assign first char to front
node curr = this.front;
this.length = original.length();
// loop through
for (int i = 0; i < original.length(); i++) {
if (i==0) {
front = new node(original.charAt(i), null);
curr = front;
}else{
curr.next = new node(original.charAt(i), null);
curr = curr.next;
}
}
}
// return length in this LString
// can use in LString constructor
public int length(){
return this.length;
}
//create and return string with contents of LString
public String toString(){
// use string builder to meet time limit
StringBuilder builder = new StringBuilder();
if(front == null){
return "";
}else{
node curr = front;
while(curr != null){
builder.append(curr.data);
curr = curr.next;
}
return builder.toString();
}
}
//compares string lists 0 if equal -1 if less, and 1 if greater
public int compareTo(LString anotherLString){
//save lowest length of strings
int minLength;
// get front spots
node curr = this.front;
node otherCurr = anotherLString.front;
// get lengths
int thisString = length();
int otherString = anotherLString.length();
// get shortest length of 2 strings
if(thisString < otherString){
minLength = thisString;
}else {
minLength = otherString;
}
//go through characters in each string and compare for lexicographic order
int iterate = 0;
while(iterate < minLength){
char string1Char = curr.data;
char string2Char = otherCurr.data;
if (string1Char != string2Char) {
return string1Char - string2Char;
}
iterate++;
curr = curr.next;
otherCurr = otherCurr.next;
}
return thisString - otherString;
}
//Return true if LString represents the same list of characters as other
@Override
public boolean equals(Object other) {
if (other == null || !(other instanceof LString))
return false;
else{
// use compareTo to determine if strings are the same
LString otherLString = (LString)other;
if(compareTo(otherLString) == 0){
return true;
}else{
return false;
}
}
}
//Return the char at the given index in this LString.
public char charAt(int index){
int length = this.length();
// check for index out of bounds
if(index < 0 || index >= length){
throw new IndexOutOfBoundsException();
}
// returns char at index
node curr = front;
for (int i = 0; i < index; i++) {
curr = curr.next;
}
return curr.data;
}
//Set the char at the given index in this LString to ch.
public void setCharAt(int index, char ch){
// check for index out of bounds
int length = this.length();
if(index < 0 || index >= length){
throw new IndexOutOfBoundsException();
}
// replaces char at index
node curr = front;
for (int i = 0; i < index; i++){
curr = curr.next;
}
curr.next = new node(curr.data,curr.next);
curr.data = ch;
}
//Returns a new LString that is a sub-string of this LString.
public LString substring(int start, int end) {
LString newLString = new LString();
// handle exceptions
if (start < 0 || start > end) {
throw new IndexOutOfBoundsException();
} else if (end > this.length()) {
throw new IndexOutOfBoundsException();
//return null in special case (empty LString)
} else if (start == end) {
//&& end == this.length()
return newLString;
} else {
node node = this.front;
for (int i = 0; i < start; i++) {
node = node.next;
// insert substring
}
node copy = new node(node.data);
newLString.front = copy;
for (int i = start + 1; i < end; i++) {
node = node.next;
copy = copy.next = new node(node.data);
}
return newLString;
}
}
// Replaces this characters in a sub-string of this LString with the characters in lStr.
public LString replace(int start, int end, LString lStr) {
// handle exceptions
if(start <0 || start >end) {
throw new IndexOutOfBoundsException();
} else if (end > this.length()) {
throw new IndexOutOfBoundsException();
}
//~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
return null;
} // end class
/*
// create new LString
LString newLString = new LString();
node node = this.front;
// to copy
node copy = new node(node.data);
// for node to replace
node replace = lStr.front;
if (start == end) {
LString newLStr = new LString();
return newLStr;
}
if (start == end && start == this.length()) {
LString newLStr = new LString();
return newLStr;
*/
}
/*
//append / prepend methods for linked list
//append
public void append(int data){
if (front == null){
front = new node(data);
end = front;
}
else {
end.next = new node(data);
end = end.next;
}
length++;
}
//prepend
public void prepend(int data){
if (front == null){
end = new node(data);
front = end;
}
else {
front = new node(data,front);
}
length++;
}
*/
replace 之前的方法返回一个新的 LString,它是此 LString 的子字符串。感谢您的帮助,谢谢。
最佳答案
如果您有追加和子序列/子字符串方法,您可以执行以下操作:
public LString replace(int start, int end, LString replacement){
//Do exception checks for start/end values here
LString replacedLs = new LString();
replacedLs.append(substring(0, start));
replacedLs.append(replacement);
replacedLs.append(substring(end, this.length));
return replacedLs;
}
关于java - 为链表类的子字符串开发替换方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35699456/