似乎无法消除该错误,查看了消除它的不同方法,但无法真正理解。
static Holding[]holding = new Holding[15];
public static void main(String[] args){
sampleData(); //Sample Data from Assignment
int options;
do{
scanner = new Scanner(System.in);
System.out.println("1. Add Holding");
System.out.println("7. Print all Holdings");
System.out.println("13. Exit");
options = scanner.nextInt();
switch(options){
case 1:
addHolding();
break;
case 7:
printHolding();
break;
default:
System.out.println("Please");
}
}while(options != 13);
System.out.println("I'm out");
}
public static void sampleData(){
holding[0] = new Book("b000001", "Intro to Java");
holding[1] = new Book("b000002", "Learning UML");
holding[2] = new Book("b000003", "Design Patterns");
holding[3] = new Book("b000004", "Advanced Java");
holding[4] = new Video("v000001", "Java 1", 4);
holding[5] = new Video("v000002", "Java 2", 6);
holding[6] = new Video("v000003", "UML 1", 6);
holding[7] = new Video("v000004", "UML 2", 4);
}
public static void printHolding(){
int option;
do{
for(Holding h : holding){
h.print();
System.out.println();
}
System.out.println("To exit press '0'");
option = input.nextInt();
}while(option != 0);
}
Exception in thread "main" java.lang.NullPointerException
at s3599741_A2.LibraryMenu.printHolding(LibraryMenu.java:307)
at s3599741_A2.LibraryMenu.main(LibraryMenu.java:71)
错误是
h.print();
和
printHolding();
在 switch 语句中。 正如您所看到的,该数组是由另一个对象组成的,例如
holding[i] = new Book("Insert ID", "Insert Title");
我写了一个这样的问题,但被标记为重复,我查看了链接
What is a NullPointerException, and how do I fix it?
但是找不到我遇到的问题或者我还没有了解的知识。有人可以解释我应该做什么吗?
Holding 的限制必须是 15,我不能使用 ArrayList 或 List。
控股类(Class):
public abstract class Holding{
private String holdingId;
private String title;
public Holding(String holdingId, String title){
this.holdingId = holdingId;
this.title = title;
}
public String getId() {
return holdingId;
}
public String getTitle(){
return title;
}
public boolean getStatus(){
return active;
}
public void print(){
System.out.println("ID: " + getId());
System.out.println("Title: " + getTitle());
}
}
最佳答案
您的holding
数组开始时填充有null
。 sampleData
仅将 holding
的八个条目(条目 0 - 7,包含在内)设置为非 null
值;这意味着条目 8 - 14(含)仍然为 null
。
这意味着这段代码将抛出:
for (Holding h : holding) {
h.print(); // Here
System.out.println();
}
要修复此问题,请添加 null
检查:
for (Holding h : holding) {
if (h != null) {
h.print();
System.out.println();
}
}
...和/或跟踪您通过实例字段添加了多少 Holding
(因为您显然不允许为此使用正确的数据结构,列表
);
static int holdingCount = 0;
...那么 sampleData
看起来像:
public static void sampleData() {
addSampleData(new Book("b000001", "Intro to Java"));
addSampleData(new Book("b000002", "Learning UML"));
addSampleData(new Book("b000003", "Design Patterns"));
addSampleData(new Book("b000004", "Advanced Java"));
addSampleData(new Video("v000001", "Java 1", 4));
addSampleData(new Video("v000002", "Java 2", 6));
addSampleData(new Video("v000003", "UML 1", 6));
addSampleData(new Video("v000004", "UML 2", 4));
}
然后
private static void addSampleData(Holding h) {
if (holdingCount < holding.length) {
holding[holdingCount++] = h;
} else {
throw new IllegalStateException("Tried to add too many holdings to array");
}
}
addHolding
会做类似的事情。
但是,这只是因为您说过不允许为此使用正确的数据结构。
关于java - 使用数组打印时出现空指针异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37495994/