java - 如何使用用户输入在 Java 中填充二维数组？

Question

我正在尝试使用用户输入的字符串来填充 Java 中的二维数组。我已经得到了字符串，并且已经弄清楚如何创建数组。我只是无法弄清楚如何将值放入数组中。如果您想知道，是的，我必须使用数组。这是我到目前为止所拥有的:

    private static int[][] parseTwoDimension(String strInput)
        {
            int rows = 0; //number of rows in the string

            for (int i = 0; i < strInput.length(); i++)
            {
                if (strInput.charAt(i) == '!') //the ! is an indicator of a new row
                {
                    rows++;
                }
            }

            int[][] arr = new int[rows][]; //create an array with an unknown number of columns
            int elementCounter = 0; //keep track of number of elements
            int arrayIndexCounter = 0; //keep track of array index

            for (int i = 0; i < strInput.length(); i++)
            {
                if (strInput.charAt(i) != '!') //while not the end of the row
                {
                    elementCounter++; //increase the element count by one
                }
                else //reached the end of the row
                {
                    arr[arrayIndexCounter] = new int[elementCounter]; //create a new column at the specified row
                    elementCounter = 0; //reset the element counter for the next row
                    arrayIndexCounter++; //increase the array index by one
                }
            }
        /*
        This is where I need the help to populate the array
        */
        char c; //each character in the string
        int stringIndex = -1; //keep track of the index in the string
        int num; //the number to add to the array
        for (int i = 0; i < arr.length; i++)
        {
            for (int j = 0; j < arr[i].length; j++)
            {
                stringIndex++; //increment string index for next element
                c = strInput.charAt(stringIndex); //the character at stringIndex
                if (c == '!') //if it is the end of the row, do nothing
                {

                }
                else //if it is not the end of the row...
                {
                    String s = Character.toString(c); //convert character to String
                    num = Integer.parseInt(s); //convert String to Integer
                    arr[i][j] = num; //add Integer to array
                }
            }
        }
        return arr; //return a two dimensional array the user defined
    }

非常感谢任何帮助:)

Answer 1

我已经编辑了您的代码并将其发布在下面。这是如何解决该问题的概述:

1. 使用 string.split("!") 用分隔符 '!' 分隔字符串。这将返回一个数组

2. 然后，使用 string.split("") 将字符串分割成单个字符

代码贴在下面:

private static int[][] parseTwoDimension(String strInput)
{
    String[] rows = strInput.split("!");    
    int[][] arr = new int[rows.length()][];

    for(int i = 0; i < rows.length; i++)
    {
        String[] elements = rows[i].split("");
        int[] intElements = new int[elements.length];

        for(int j = 0; j < elements.length; j++)
        {
            intElements[j] = Integer.parseInt(elements[j]);
        }
        arr[i] = intElements;
    }
}

请告诉我这是否有效。 string.split() 函数在将字符串解析为数组时非常有用