我正在编写一个 IP 扫描器应用程序，这个过程需要很长时间，所以我在 gui 的后台使用的是服务执行器，如下所示:
public static List<Future<String>> checkThisIP(String ipStart, String ipEnd) throws UnknownHostException {
final ExecutorService es = Executors.newFixedThreadPool(10);
final List<Future<String>> futures = new ArrayList<>();
String ipStringStart;
String ipStringEnd;
String targetIpString;
//my update
ipStringStart = ipStart.substring(ipStart.lastIndexOf(".") + 1, ipStart.length());
ipStringEnd = ipEnd.substring(ipEnd.lastIndexOf(".") + 1, ipEnd.length());
targetIpString = ipStart.substring(0, ipStart.lastIndexOf(".") + 1);
if (!ipStart.equals(ipEnd)) {
for (int i = Integer.parseInt(ipStringStart); i <= Integer.parseInt(ipStringEnd); i++) {
String currentIp = targetIpString + i;
futures.add(runPingScan(es, currentIp));
}
} else {
futures.add(runPingScan(es, ipStart));
}
es.shutdown();
return futures;
}
public static Future<String> runPingScan(final ExecutorService es, final String ip) {
return es.submit(new Callable<String>() {
@Override
public String call() {
String returnMe = "";
//custom ping class
Ping p = new Ping();
//send message
p.SendReply(ip);
//IsReachable returns ture or false
if(p.IsReachable()){
returnMe=ip;
}
return returnMe;
}
});
}
这是使用 Jbutton 执行的原始延迟代码操作:
// scan result is Future list returned from service executor
List<Future<String>> scanResult = p.checkThisIP(jFormattedTextField1.getText(), jFormattedTextField2.getText());
for (final Future<String> f : scanResult) {
try {
ip = f.get();
if (!ip.equals("")) {
arp ARP = new arp();
PortScan openPort = new PortScan();
IP ipClass = new IP();
mac = ARP.getMac(ip);
manufacturer = ARP.getOUI(mac);
ports = openPort.checkIpForPorts(ip);
hostname = ipClass.hostname(ip);
title = ipClass.htmlTitle(ip);
Object[] data = {ip, mac, manufacturer, ports, hostname, title};
tableModel.addRow(data);
}
if (jFormattedTextField1.getText().equals(jFormattedTextField2.getText()) && ip.equals("")) {
JOptionPane.showMessageDialog(null, "<html>Can not ping the address ! <br> Server might be protected by <b>WAF</b>.</html>", "Alert", HEIGHT);
}
} catch (Exception ex) {
Logger.getLogger(gui.class.getName()).log(Level.SEVERE, null, ex);
}
}
运行此代码很好，但是当我将其附加到开始扫描按钮时，GUI 滞后，我在谷歌上搜索并发现使用Swing Worker。当我单独实现 Swing Worker 时，它杀死了并发性，而当我实现两个 GUI 时，它仍然滞后。我的问题是无论如何都要让按钮(Swing 工作线程)调用服务执行器来执行其他进程？
最佳答案
我已经成功地通过实现 Swing Worker 来解决我的问题，并且函数在后台执行将为服务执行器启动一个新线程并防止延迟。
//The actionpreformed by the button
SwingWorker worker = new SwingWorker<Void, Void>() {
@Override
// All actions are done this method
protected Void doInBackground() throws Exception {
String ip = "";
String mac = "";
String manufacturer = "";
String ports = "";
String hostname = "";
String title = "";
tableModel.setRowCount(0);
PingScan p = new PingScan();
List<Future<String>> scanResult = p.checkThisIP(jFormattedTextField1.getText(), jFormattedTextField2.getText());
for (final Future<String> f : scanResult) {
try {
ip = f.get();
if (!ip.equals("")) {
arp ARP = new arp();
PortScan openPort = new PortScan();
IP ipClass = new IP();
mac = ARP.getMac(ip);
manufacturer = ARP.getOUI(mac);
ports = openPort.checkIpForPorts(ip);
hostname = ipClass.hostname(ip);
title = ipClass.htmlTitle(ip);
Object[] data = {ip, mac, manufacturer, ports, hostname, title};
tableModel.addRow(data);
}
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
return null;
}
};
worker.execute();
关于java - 如何从 Swing Worker 运行服务执行器？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/42228574/