查看了其他相关帖子,但似乎没有任何效果。
基本上,我想弄清楚如何将数据传递到我的restful spring-boot应用程序。
这是我正在使用的curl命令:
$ curl -iX POST -H 'Content-Type: application/json' -d @args.json http://localhost:8080/myapp/dummyApi
args.json
包含:
文件:args.json:
{
"arg1": "hello",
"arg2": 10,
"arg3": {
"a": "1",
"b": "2"
}
}
API 在 MyController.java
中定义如下:
文件:MyController.java
@RestController
@RequestMapping("/myapp")
public class MyController {
//...
static class DummyRet {
private String foo;
public DummyRet(String f) {
foo = f;
}
public String getFoo() {
return foo;
}
public void setFoo(String foo) {
this.foo = foo;
}
}
@RequestMapping(value="/dummyApi", method=RequestMethod.POST)
public DummyRet dummyApi(@RequestParam(value = "arg1", required = false, defaultValue = "") String arg1,
@RequestParam(value = "arg2", required = false, defaultValue = "") Long arg2,
@RequestParam(value = "arg3", required = false) Map<String, String> arg3) {
LOGGER.info(">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>");
LOGGER.info("Arguments received:");
LOGGER.info("arg1: " + arg1);
LOGGER.info("arg2: " + arg2);
LOGGER.info("arg3: " + arg3);
LOGGER.info(">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>");
return new DummyRet("foo");
}
//...
}
curl 命令的返回结果为 200 成功(因为不需要任何参数),但 args 的值未到达 dummyApi
方法
$ curl -iX POST -H 'Content-Type: application/json' -d @args.json http://localhost:8080/myapp/dummyApi
HTTP/1.1 200
Content-Type: application/json;charset=UTF-8
Transfer-Encoding: chunked
Date: Sun, 04 Jun 2017 15:37:42 GMT
{"foo":"foo"}
服务器控制台如下所示:
2017-06-04 18:17:56.818 DEBUG 32258 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet : DispatcherServlet with name 'dispatcherServlet' processing POST request for [/myapp/dummyApi]
2017-06-04 18:17:56.818 DEBUG 32258 --- [nio-8080-exec-7] s.w.s.m.m.a.RequestMappingHandlerMapping : Looking up handler method for path /myapp/dummyApi
2017-06-04 18:17:56.818 DEBUG 32258 --- [nio-8080-exec-7] s.w.s.m.m.a.RequestMappingHandlerMapping : Returning handler method [public com.xx.controllers.MyController$DummyRet com.xx.controllers.MyController.dummyApi(java.lang.String,java.lang.Long,java.util.Map<java.lang.String, java.lang.String>)]
2017-06-04 18:17:56.819 INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController : >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
2017-06-04 18:17:56.819 INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController : Arguments received:
2017-06-04 18:17:56.819 INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController : arg1:
2017-06-04 18:17:56.819 INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController : arg2: null
2017-06-04 18:17:56.819 INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController : arg3: null
2017-06-04 18:17:56.819 INFO 32258 --- [nio-8080-exec-7] c.p.controllers.MyController : >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
2017-06-04 18:17:56.819 DEBUG 32258 --- [nio-8080-exec-7] m.m.a.RequestResponseBodyMethodProcessor : Written [com.xx.controllers.MyController$DummyRet@c35d46f] as "application/json" using [org.springframework.http.converter.json.MappingJackson2HttpMessageConverter@301ec38b]
2017-06-04 18:17:56.819 DEBUG 32258 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet : Null ModelAndView returned to DispatcherServlet with name 'dispatcherServlet': assuming HandlerAdapter completed request handling
2017-06-04 18:17:56.819 DEBUG 32258 --- [nio-8080-exec-7] o.s.web.servlet.DispatcherServlet : Successfully completed request
我希望我没有遗漏任何重要的细节,但如果有任何遗漏,请告诉我。
最佳答案
这有效:
我的 spring-boot java 方法有两个问题,
- 我为参数指定了
@RrequestParam
,而我应该使用@RequestBody
- 我有多个此类方法参数,在 POST 中它应该是一个(参见脚注)
@RequestBody
但是由于我需要将多个参数传递给该方法,解决方案是将这些参数包装在支持对象中,如下所示:
public static class Args {
// members
private String arg1;
private Long arg2;
private Map<String, String> arg3;
// accessors
public String getArg1() {return arg1;}
public void setArg1(String arg1) {this.arg1 = arg1;}
public Long getArg2() {return arg2;}
public void setArg2(Long arg2) {this.arg2 = arg2;}
public Map<String, String> getArg3() {return arg3;}
public void setArg3(Map<String, String> arg3) {this.arg3 = arg3;}
}
接收者方法将是:
@RequestMapping(value="/dummyApi", method=RequestMethod.POST)
public DummyRet dummyApi(@RequestBody Args args) {
LOGGER.info(">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>");
LOGGER.info("Arguments received:");
LOGGER.info("arg1: " + args.getArg1().toString());
LOGGER.info("arg2: " + args.getArg2().toString());
LOGGER.info("arg3: " + args.getArg3().toString());
LOGGER.info(">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>");
return new DummyRet("foo");
}
脚注:事实上,可以通过自定义实现传递多个参数,如 this 中所述。所以回应。没试过
关于java - 将 json 数据传递给 spring-boot 应用程序的 Curl POST 命令不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44358942/