我的json:
{
"d": {
"a": {
"someId": null,
"e": "8"
},
"p": {
"m": "t"
}
}
}
我正在使用
gson.fromJson(ResourceUtils.getStringFromInputStream(inputStream), MyClass.class);
我的类(class)
{
public D d;
}
D {
public A a;
public P p;
}
A {
public String someId;
public String e;
}
P {
public String m;
}
但是当我运行它时:
com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected STRING but was NULL at path $.someId
所以基本上我想从 android 应用程序中的 json 文件创建一个对象。我正在使用 gson 来实现这一点。但 null 值未正确设置。
最佳答案
Gson 默认行为是“忽略”空属性。您可以调用serializeNulls来更改此行为:
Configure Gson to serialize null fields. By default, Gson omits all fields that are null during serialization.
示例:
public static void main (String args[])
{
GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.serializeNulls();
Gson gson = gsonBuilder.create();
String filename="path2/theJsonFile";
try {
JsonReader read= new JsonReader(new FileReader(filename));
MyClass myclass= gson.fromJson(read, MyClass.class);
System.out.println(gson.toJson(myclass));
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
输出将是:
{"d":{"a":{"someId":null,"e":"8"},"p":{"m":"t"}}}
关于java - GSON将json转换为类对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49807148/