您能帮我解释一下我应该如何传递作者值吗？
@GetMapping(value = "/search")
public ResponseEntity<List<Book>> searchBooksByTitleAndAuthor(
@RequestParam(value = "title", required = false) final String title,
@RequestParam(value = "author", required = false) final Author author) {
HttpStatus httpStatus = HttpStatus.OK;
List<Book> books = null;
if (title == null && author == null) {
log.info("Empty request");
httpStatus = HttpStatus.BAD_REQUEST;
} else if (title == null || author == null) {
books = bookService.getBooksByTitleOrAuthor(title, author);
} else {
Optional<Book> book = bookService.getBookByTitleAndAuthor(title, author);
if (book.isPresent()) {
books = Arrays.asList(book.get());
}
}
if (books == null) {
return new ResponseEntity<>(httpStatus);
} else {
return new ResponseEntity<>(books, httpStatus);
}
}
和 Author 类看起来像:
@Entity
@NoArgsConstructor
@AllArgsConstructor
@Getter
@EqualsAndHashCode
@ToString
public final class Author {
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Long id;
private String name;
private LocalDate dateOfBirth;
private String bio;
}
在这种情况下使用author或@RequestParam而不是请求正文是一个好方法吗？ 我考虑过仅请求作者姓名的字符串，但这会影响服务的方法。
最佳答案
根据https://lankydanblog.com/2017/03/11/passing-data-transfer-objects-with-get-in-spring-boot/ ，...您可以(在 author.dateOfBirth 上设置一些转换注释后):
在字符串参数上使用
@RequestParam(并让您的 Controller /某人 进行转换):..., @RequestParam(value = "author", required = false) final String author) { ...final Author author = new ObjectMapper().setDateFormat(simpleDateFormat) .readValue(author, Author.class);在这种情况下，您会请求:
http://localhost:8080/myApp/search?title=foo&author={"id"="1",...}或者:省略
@RequestParam，但传递对象(并让 spring 负责转换):...(@RequestParam(value = "title", required = false) final String title, final Author author)并请求如下:
http://localhost:8080/myApp/search?title=foo&id=1&name=Donald E. Knuth&...
另请参阅:
关于java - 如何将对象作为 URI 行中的查询参数传递？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50429117/