@Entity
@Table(name="seance")
@Data
public class Seance {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(nullable = false, unique = true)
private Integer id;
private java.time.LocalTime displayTime;
@ManyToMany(mappedBy = "seances")
@JsonIgnore
private List<Repertoire> repertoires = new ArrayList<>();
@OneToMany(mappedBy = "reservationSeance", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@JsonIgnore
private List<Reservation> reservations = new ArrayList<>();
}
@Entity
@Table(name="reservation")
@Data
public class Reservation {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(nullable = false, unique = true)
private Integer id;
private java.time.LocalDate reservationDate;
@ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(name = "id_seance")
private Seance reservationSeance;
.........
}
我有两个与 ManyToOne 相关的实体,并且我尝试扩展 JpaRepository
public interface ReservationRepository extends JpaRepository<Reservation,Integer> {
List<Reservation> findReservationsByReservationSeance(Seance seance);
}
但是作为参数,我必须使用所有对象 Seance,可以使用 JpaRepository 仅通过 Seance 表中的 id 和 displayTime 查找预订,还是需要编写自己的方法?
最佳答案
您可以在 ReservationRepository
中添加您自己的查询
@Query("SELECT r FROM Reservation r WHERE r.reservationSeance.id=:seanceId AND r.reservationSeance.displayTime = :displayTime")
public List<Reservation> findReservations(@Param("seanceId") int seanceId, @Param("displayTime") LocalTime displayTime);
关于java - JpaRepository findBy 引用表中的字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51245892/