我在抽屉导航中有两个 fragment ListNav和SwipeNav。 ListNav 显示字符串数组中数据的 ListView 。 SwipeNav 将数据显示为字符串数组中相同数据的滑动 View 。
我正在使用单个 fragment 进行 viewpager 滑动 View 多个选项卡。
我的问题是:
When I click on B in List View, it shows A in SwipeNav,
When I click on C in List View, it shows A in SwipeNav,
When I click on D in List View, it shows A in SwipeNav,
When I click on E in List View, it shows A in SwipeNav,
我想得到结果:
If I click on B in List View, it will show B in SwipeNav,
If I click on C in List View, it will show C in SwipeNav,
If I click on D in List View, it will show D in SwipeNav
字符串数组:
<string-array name="tab_titles">
<item>A</item>
<item>B</item>
<item>C</item>
<item>D</item>
<item>E</item>
<item>F</item>
<item>G</item>
<item>H</item>
<item>I</item>
........
</string-array>
我在下面使用 ListNav 将 SwipeNav 替换为 OnItemClickListener:
列表导航:
public class ListNav extends Fragment {
@Nullable
@Override
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
//returning our layout file
//change R.layout.yourlayoutfilename for each of your fragments
return inflater.inflate(R.layout.nav_lis_layout, container, false);
}
@Override
public void onViewCreated(View view, Bundle savedInstanceState) {
super.onViewCreated(view, savedInstanceState);
FragmentManager fm=getFragmentManager();
FragmentTransaction ft = fm.beginTransaction();
ft.add(R.id.fragment12, new ListNavAdapter());
ft.commit();
列表导航适配器:
public class ListNavAdapter extends ListFragment {
@Override
public View onCreateView(LayoutInflater inflater,
ViewGroup container, Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.nav_list_layout, container, false);
return view;
}
@Override
public void onActivityCreated(Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState);
ArrayAdapter adapter = ArrayAdapter.createFromResource(getActivity(),
R.array.tab_titles, android.R.layout.simple_list_item_1);
setListAdapter(adapter);
getListView().setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
String[] tabTitlesArray = getContext().getResources().getStringArray(R.array.tab_titles);
Bundle bundle = new Bundle();
bundle.putString("tab_titles", tabTitlesArray[i].toString());
SwipeNav fragobj = new SwipeNav();
fragobj.setArguments(bundle);
FragmentManager fm=getFragmentManager();
FragmentTransaction ft = fm.beginTransaction();
ft.replace(((ViewGroup)(getView().getParent())).getId(), fragobj);
ft.addToBackStack(null);
ft.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_FADE);
ft.commit();
}
});
}
在滑动导航中:
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
if (getArguments() != null && !getArguments().isEmpty()) {
Bundle bundle = this.getArguments();
String myInt = bundle.getString("tab_titles");
}
return inflater.inflate(R.layout.nav_swipe, container, false);
}
@Override
public void onViewCreated(View view, Bundle savedInstanceState) {
super.onViewCreated(view, savedInstanceState);
myPagerAdapter = new MyPagerAdapter(getChildFragmentManager(),getContext());
viewPager = (ViewPager) view.findViewById(R.id.pager);
viewPager.setAdapter(myPagerAdapter);
}
这是 MyPagerAdapter:
public class MyPagerAdapter extends FragmentStatePagerAdapter {
private Context context;
private String[] tabTitlesArray = null;
public MyPagerAdapter(FragmentManager fm, Context context) {
super(fm);
tabTitlesArray = context.getResources().getStringArray(R.array.tab_titles);
this.context= context;
}
@Override
public Fragment getItem(int i) {
Fragment fragment = new AFragment();
Bundle args = new Bundle();
args.putString(AFragment.ARG_OBJECT, tabTitlesArray[i]);
fragment.setArguments(args);
return fragment;
}
@Override
public int getCount() {
return tabTitlesArray.length;
}
@Override
public CharSequence getPageTitle(int position) {
return "OBJECT " + (position + 1);
}
}
选项卡式 Activity AFragment 的单个 fragment :
public class AFragment extends Fragment {
public static final String ARG_OBJECT = "object";
public AFragment() {
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
// The last two arguments ensure LayoutParams are inflated
// properly.
View rootView = inflater.inflate(R.layout.fragment_a, container, false);
Bundle args = getArguments();
((TextView) rootView.findViewById(R.id.text1)).setText(args.getString(ARG_OBJECT));
return rootView;
}
nav_lis_layout:
<?xml version="1.0" encoding="utf-8"?>
<FrameLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/fragment12"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
导航列表布局:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<ListView
android:id="@android:id/list"
android:layout_width="match_parent"
android:layout_height="wrap_content" >
</ListView>
</LinearLayout>
我在 Stackoverflow 中搜索了所有答案。但未能解决我的问题,为什么特定项目单击不向下一个 fragment 显示相同的项目。 我需要你的帮助。
最佳答案
你不应该在字符串中放入逗号
"tabTitlesArray[i]"
尝试使用
""+tabTitlesArray[i]
关于java - Android 在 fragment 之间传递字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55373351/