java - 没有外键的 JPA OneToOne 关联总是失败

Question

我是 JPA/Hibernate 新手， 我正在创建一个简单的联接来获取不同表中的一些数据 让我们看看这样:

目的是根据 M_USER.username 列获取 M_PROFILE 数据，但显然您会看到 M_PROFILE 表中没有外键。

我只是尝试使用下面的代码，但没有结果并且总是出错。

用户实体类

@Entity
@Table(name = "M_USER")
public class User {

        @Id
        @Column(name = "id")
        private String uuid;

        @Column(name = "email")
        private String email;

        @Column(name = "username")
        private String username;

        @OneToOne(fetch = FetchType.LAZY)
        @MapsId("username")
        private Profile profile;

        public String getId() {
            return id;
        }
        public void setId(String id) {
            this.id = id;
        }

        public String getEmail() {
            return email;
        }
        public void setEmail(String email) {
            this.email = email;
        }

        public String getUsername() {
            return username;
        }
        public void setUsername(String username) {
            this.username = username;
        }

        public Profile getProfile() {
            return profile;
        }
        public void setProfile(Profile profile) {
            this.profile = profile;
        }
    }

配置文件实体类

@Entity
@Table(name = "M_PROFILE")
public class Profile {

    private String username;
    private String phone;
    private String address;

    @Id
    @Column(name = "username", nullable = false)
    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    @Basic
    @Column(name = "phone")
    public String getPhone() {
        return phone;
    }

    public void setPhone(String phone) {
        this.phone = phone;
    }

    @Basic
    @Column(name = "address")
    public String getAddress() {
        return address;
    }

    public void setAddress(String address) {
        this.address = address;
    }
}

调用时出现不同的错误

User user = userRepository.findByUsername("aswzen");
String phone = user.getProfile().getPhone();

例如这个。

"USER0_"."PROFILE_USERNAME": invalid identifier

需要帮助，提前致谢，

注意:我没有权限更改表格..

Answer 1

不要忘记禁用 JoinColumn 的可插入和可更新

@OneToOne
@JoinColumn(name = "username", referencedColumnName = "username", updatable = false, insertable = false)
private profile profile;