Java Socket Server 在读取数据时挂起

Question

我有一个与 Java 套接字服务器通信的 PHP 文件，当我发送数据时，我的 Java 服务器在 inputLine = in.readLine() 上卡住(挂起、卡住)。我调试了一下，发现只有读取数据的时候才会出现这种情况。

这是我的服务器 java 方法:

public void start_echo_server(int port){
    main.getProxy().getConsole().sendMessage(new TextComponent(ChatColor.GOLD + "STARTING SOCKET LISTENER (echo)"));

    int portNumber = port;
    try {
        ServerSocket serverSocket = new ServerSocket(portNumber);
        Socket clientSocket = serverSocket.accept();
        // accepted the connection
        main.getProxy().getConsole().sendMessage(new TextComponent(ChatColor.GOLD + "ACCEPTED"));
        // in stream
        BufferedReader in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
        // outstream
        PrintWriter out = new PrintWriter(clientSocket.getOutputStream(), true);

        String inputLine;
        StringBuilder sb = new StringBuilder();
        while ((inputLine = in.readLine()) != null) {
            sb.append(inputLine);
        }
        String final_line = sb.toString();
        main.getProxy().getConsole().sendMessage(new TextComponent(ChatColor.GOLD + "IN: " + final_line));
        //String final_ret = parser.parse_message(final_line);
        //main.getProxy().getConsole().sendMessage(new TextComponent(ChatColor.GOLD + "FINAL: " + final_ret));
        out.println(final_line);
        in.close();
        out.close();
        serverSocket.close();
    } catch (IOException e) {
        e.printStackTrace();
    }
}

这是我的 PHP 文件:

    <?php
  if( isset($_POST['username']) )
  {
     $username = $_POST['username'];
     parse($username);
  }else{
    echo "Missing parameters!";
    exit();
  }
  function parse($username){
    //Must be same with server
    $host = "127.0.0.1";
    $port = 59090;
    // No Timeout
    //Create Socket
    $sock = socket_create(AF_INET, SOCK_STREAM, 0) or die("Could not create socket\n");
    //Connect to the server
    $result = socket_connect($sock, $host, $port) or die("Could not connect toserver\n");
    $message = "player_online ". $username;
    //Write to server socket
    $len = strlen($message);

    socket_write($sock, $message, $len) or die("SENDING ERROR ". $message ." \n");
    //Read server respond message
    $result = socket_read($sock, 1024) or die("RESPONSE ERROR ". $message ." \n");
    echo "Reply From Server  :".$result;
    //Close the socket
    socket_close($sock);
  }
?>

问题是当我在 PHP 端执行 socket_write (写入数据)时，但问题出在 java 行 while ((inputLine = in.readLine()) ! =空){。

非常感谢!

Answer 1

解决了!

我正在读取多行，但只有一行进来，而消息后面没有包含换行符 (\n)(这表示上一条消息是已完成的行) )。 替换 PHP $message = "player_online "。 $username; 与 $message = "player_online "。 $用户名 ."\n";

还得更换Java

String inputLine;
StringBuilder sb = new StringBuilder();
while ((inputLine = in.readLine()) != null) {
    sb.append(inputLine);
}
String final_line = sb.toString();

与

String inputLine = in.readLine();
String final_line = inputLine;