如何在 executorService.submit() 回调中添加自定义检查。 我希望我的线程在标志为 true 时不要执行任何操作。如果 flag 为 false 那么它应该照常工作。
import org.apache.commons.lang3.concurrent.BasicThreadFactory;
import java.util.concurrent.Callable;
import java.util.concurrent.Future;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class test{
private static volatile boolean flag= false;
public static void main(String[] args) throws ExecutionException, InterruptedException {
Callable<Boolean> callableTask = () -> {
return isFlag();
};
Future a = submitAsync(callableTask);
System.out.println("tartest"+a.get());
}
public static Future submitAsync(Callable taskToRun) {
ExecutorService e1 = Executors.newSingleThreadExecutor(new BasicThreadFactory.Builder().namingPattern("").build());
return e1.submit(() -> {
try {
if (flag) {
return;
}
taskToRun.call();
} catch (Exception e) {
System.out.println("garbage ---");
}
});
// return e1.submit(taskToRun);
}
public static boolean isFlag() {
return true;
}
}
这里,a.get() 返回 null。如果我用 e1.submit(taskToRun) 替换 e1.submit(....) ,它在给定的代码片段中被注释,那么它的工作正常。那么为什么 a.get() 为 null?
最佳答案
return e1.submit(() -> {
try {
if (flag) {
return;
}
taskToRun.call();
} catch (Exception e) {
System.out.println("garbage ---");
}
});
在此代码段中,传递给 ExecutorService e1
上的 submit
方法的 lambda 被解释为 Runnable
,这就是返回值为空
。检查这个documentation更多细节。您需要将可调用的 taskToRun
本身传递给 e1.submit()
才能获取可调用的返回值。此外,将逻辑放在 Callable 本身内部会更清晰。
我重写了示例代码来满足您的要求。
package stackoverflow.test;
import org.apache.commons.lang3.concurrent.BasicThreadFactory;
import java.util.concurrent.Callable;
import java.util.concurrent.Future;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class test{
private static volatile boolean flag = true;
public static void main(String[] args) throws ExecutionException, InterruptedException {
Callable<Boolean> callableTask = () -> {
if (flag) {
System.out.println("Flag is true, returning without executing callable logic !");
return false;
}
System.out.println("Flag is false, executing callable logic !");
return isFlag();
};
Future a = submitAsync(callableTask);
System.out.println("test " + a.get());
}
private static Future<Boolean> submitAsync(Callable<Boolean> taskToRun) {
ExecutorService e1 = Executors.newSingleThreadExecutor(new BasicThreadFactory.Builder().namingPattern("").build());
return e1.submit(taskToRun);
}
private static boolean isFlag() {
return true;
}
}
关于java - 当提交带有回调的可调用任务时,ExecutorService 是如何工作的,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58326435/