Java将for循环转换为lambda表达式

Question

我想将下面的代码转换为lamda表达式，尤其是粗体标记的FOR循环，从第一个索引开始并跳过下一个索引[i=i+2]

public static List<Integer>  integerArrayList = Arrays.asList(0, 1, 2, 3, 4, 5, 6);

  Thread oddThread8 = new Thread(() -> {
  List<Integer> integerArrayList = ReadList8Refctor.getIntegerList();
  int listSize = integerArrayList.size();

  for(int i=1; i<listSize; i=i+2) {
       System.out.println(Thread.currentThread().getName()+" - "+integerArrayList.get(i));
     }

}, "ODD");

我得到了完美的输出，帮助我重构FOR循环，提前致谢

ODD - 1
ODD - 3
ODD - 5
EVEN - 0
EVEN - 2
EVEN - 4
EVEN - 6

Answer 1

如果您使用的是 java-9，您可以使用:-

 IntStream.iterate(1,i -> i < listSize ,i ->i+2).forEach(i -> Thread.currentThread().getName()+" - "+integerArrayList.get(i));

在 java-8 上:-

 IntStream.range(1,listSize).filter(value -> value%2!=0).forEach(i -> Thread.currentThread().getName()+" - "+integerArrayList.get(i));