java - 在元音和辅音之间添加空格？

Question

请有人帮我在元音和辅音之间添加空格。结果应该类似于 ae bc i

public static void main(String[] args) {
        String str = "aebci";

        StringBuilder sb = new StringBuilder();
        for (int i = 0; i < str.length()-1; i++) {
            if ((str.charAt(i) == 'a' || str.charAt(i) == 'e' || str.charAt(i) == 'i' || str.charAt(i) == 'o' || str.charAt(i) == 'u' ) &&
                 (str.charAt(i+1) != 'a' || str.charAt(i+1) != 'e' || str.charAt(i+1) != 'i' || str.charAt(i+1) != 'o' || str.charAt(i+1) != 'u' ))    {
                sb.append(" ");
            }
                sb.append(str.charAt(i));
        }
        System.out.println(sb.toString());;
    }
}

Answer 1

当字符串包含彼此靠近的元音和辅音时，您需要找到所有位置。可以使用正则表达式:

public static void main(String[] args) {
    String str = "aebci";
    Pattern pattern = Pattern.compile("([aeiou][^aeiou])|([^aeiou][aeiou])");
    Matcher matcher = pattern.matcher(str);

    StringBuffer buffer = new StringBuffer();
    while (matcher.find()) {
        String group = matcher.group(); // two symbols
        matcher.appendReplacement(buffer, group.charAt(0) + " " + group.charAt(1));
    }
    matcher.appendTail(buffer);
    System.out.println(buffer.toString());
}

输出:

ae bc i