我正在尝试为按名称查找玩家的服务层方法编写单元测试。该方法调用 JPA 存储库方法并返回 Page 对象。 我希望测试验证是否确实调用了存储库中的正确方法。
测试类
@RunWith(SpringRunner.class)
@SpringBootTest(classes = {PlayerService.class})
public class PlayerServiceTest {
@Autowired
PlayerService playerService;
@MockBean
PlayerRepository playerRepository;
@Test
public void whenListPlayersByName_thenShouldCallFindMethodWithPageableArgAndNameArg(){
Pageable pageableStub = Mockito.mock(Pageable.class);
String name = "xxx";
Mockito.when(playerRepository.findByNameContainingIgnoreCase(any(String.class), any(Pageable.class)))
.thenReturn(any(Page.class));
//1st attempt:
//playerService.listPlayersByName(name, pageableStub);
playerService.listPlayersByName(eq(name), pageableStub);
verify(playerRepository).findByNameContainingIgnoreCase(any(String.class), any(Pageable.class));
}
我的问题
测试失败并显示消息:
org.mockito.exceptions.misusing.InvalidUseOfMatchersException:
Invalid use of argument matchers!
2 matchers expected, 1 recorded:
-> at com.domin0x.player.PlayerServiceTest.whenListPlayersByName_thenShouldCallFindMethodWithPageableArgAndNameArg(PlayerServiceTest.java:60)
This exception may occur if matchers are combined with raw values:
//incorrect:
someMethod(anyObject(), "raw String");
When using matchers, all arguments have to be provided by matchers.
For example:
//correct:
someMethod(anyObject(), eq("String by matcher"));
按照建议,我将 name
更改为 eq(name)
,但这会导致不同的问题:
Argument(s) are different! Wanted:
com.domin0x.player.PlayerRepository#0 bean.findByNameContainingIgnoreCase(
<any java.lang.String>, <any org.springframework.data.domain.Pageable>);
Actual invocation has different arguments:
com.domin0x.player.PlayerRepository#0 bean.findByNameContainingIgnoreCase(
null, Mock for Pageable, hashCode: 309271464
;
有什么建议我应该在测试中更改什么吗?
服务类别
@Service
public class PlayerService {
public Page<Player> listPlayersByName(String name, Pageable pageable) {
return repository.findByNameContainingIgnoreCase(name, pageable);
}
存储库界面
@Repository
public interface PlayerRepository extends JpaRepository<Player, Integer> {
Page<Player> findByNameContainingIgnoreCase(String name, Pageable pageable);
}
最佳答案
我花了一段时间才弄清楚这个问题。
在thenReturn
中,您正在调用any(Page.class)
。相反,您应该返回实际的 Page
对象或模拟 Page
对象。
最好避免使用“any”,除非您无法知道其身份。
Page<Player> pageStub = (Page<Player>)Mockito.mock(Page.class);
Mockito.when(playerRepository.findByNameContainingIgnoreCase(name, pageableStub))
.thenReturn(pageStub);
Page<PlayerStub> result = playerService.listPlayersByName(name, pageableStub);
assertSame(pageStub, result);
// No need to call verify, since it couldn't get pageStub without calling the correctly stubbed method.
澄清一下:eq()
、any()
和其他“匹配器”只能用作 when
中方法的参数并验证
。它们不应该传递给测试对象,也不应该从任何模拟对象返回。
关于java - Spring Boot 服务层单元测试中模拟原始字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60306567/