java - 对 LinkedList 中具有相同值的项目进行排序？？？ - java

Question

我在尝试对 LinkedList 进行排序时遇到问题。 我使用了以下代码:

Collections.sort(mylist, new Comparator<String[]>() {
            public int compare(String[] o1, String[] o2) {
                int one= Integer.parseInt(o1[1]);
                int two = Integer.parseInt(o2[1]);
                return one-two;
            }
        });

这里我输入了一些值:

    thelist.testing("a",1);
    thelist.testing("b",5);
    thelist.testing("c",5);
    thelist.testing("d",5);
    thelist.testing("e",7);
    System.out.println(thelist);

我有这些结果:a:1,b:5,c:5,d:5,e:7

当项目具有相同编号时，我希望输出如下:a:1,d:5,c:5,b:5,e:7

Answer 1

就这样做:

Collections.sort(mylist, new Comparator<String[]>() {  
            public int compare(String[] o1, String[] o2) {  
                if(o1[1].equals(o2[1]){  
                   return -(o1[0].compareTo(o2[0]));
                }  

                int one= Integer.parseInt(o1[1]);
                int two = Integer.parseInt(o2[1]);
                return one-two;
            }
        });

示例代码:

List<String[]> mylist = new ArrayList<String[]>();  
mylist.add(new String[]{"a","1"});  
mylist.add(new String[]{"b","5"});  
mylist.add(new String[]{"c","5"});  
mylist.add(new String[]{"d","5"});  
mylist.add(new String[]{"e","7"});  

输出:

[a, 1]  
[d, 5]  
[c, 5]  
[b, 5]   
[e, 7]