java - 通过数组列表搜索？ java

Question

你好，所以我的问题中有两个数组列表，一个填充了前 1000 个女孩名字及其使用次数，另一个填充了前 1000 个男孩名字及其使用次数。用户输入一个名字，搜索两个数组列表，然后输出该名字是否在男孩或女孩的名字中，他们的排名以及他们被使用的次数。如果该名字位于前 1000 个男孩名字中，则还需要输出 The name is not apart of the top 1000 boy name，如果是男孩名字则相同。这就是我所拥有的

  public void search()
  {
    Scanner keyboard = new Scanner(System.in);
    System.out.println("Please enter the name you would like to search.");
    nameSearch = keyboard.next();

    for(int i = 0; i < girls.size(); i++)
    {
      if(nameSearch.equals(girls.get(i).getName()))
      {
        System.out.println(nameSearch + " is ranked " + (i+1) + " in popularity among girls with " + girls.get(i).getAmount() + " namings.");
      }

    }


    else
      System.out.println(nameSearch + " is not in the top 1000 girl names.");


    for(int i = 0; i < boys.size(); i++)
    {
      if(nameSearch.equals(boys.get(i).getName()))
      {
        System.out.println(nameSearch + " is ranked " + (i+1) + " in popularity among boys with " + boys.get(i).getAmount() + " namings.");
      }
    }


    else
      System.out.println(nameSearch + " is not in the top 1000 boys names.");

  }

显然我收到了一个错误，因为我不能有一个 else 语句，前面没有 if 。一切都有效，只要搜索数组并找到排名以及我只需要它输出正确的东西即可。我完全不知道该怎么做才能让它发挥作用。

更新-我尝试了 contains 方法，但我永远无法让它工作。当我知道它是存在的名称时，它总是输出它无法在两个数组中找到该名称。如果这看起来有问题，请告诉我，因为它无法正常工作

谢谢! ——杰西

   Scanner keyboard = new Scanner(System.in);
    System.out.println("Please enter the name you would like to search.");
    nameSearch = keyboard.next();

    if(girls.contains(nameSearch))
    {
      for(int i = 0; i < girls.size(); i++)
      {
        if(nameSearch.equals(girls.get(i).getName()))
        {
          System.out.println(nameSearch + " is ranked " + (i+1) + " in popularity among girls with " + girls.get(i).getAmount() + " namings.");
        }
      }
    } 
    else
      System.out.println(nameSearch + " is not in the top 1000 girl names.");



    if(boys.contains(nameSearch))
    {
      for(int i = 0; i < boys.size(); i++)
      {
        if(nameSearch.equals(boys.get(i).getName()))
        {
          System.out.println(nameSearch + " is ranked " + (i+1) + " in popularity among boys with " + boys.get(i).getAmount() + " namings.");
        }
      }
    } else
     {
      System.out.println(nameSearch + " is not in the top 1000 boys names.");
     }

Answer 1

您可以检查它是否包含它:

if(girls.contains(nameSearch)) {
   // Look for the data
} else {
   // print error
}