Java程序找到字符串中出现次数最多的字符？

Question

这是我到目前为止得到的代码......

import java.util.Scanner;
class count{
    public static void main(String args[]){
        Scanner s=new Scanner(System.in);
        System.out.println("Enter a string");
        String sent=s.nextLine();
        int len = sent.length();
        int arr[]=new int[len];
        int count=1;
        char ch[] = new char[len];
        for(int i = 0; i <= len-1; i ++)
        {
            ch[i] = sent.charAt(i);

        }
        for(int j= 0;j<=len-1;j++){
            for(int k=0;k<=len-1;k++){
                if(ch[j]==ch[k]){
                    arr[j]= count++;
                }
            }
        }

        int max=arr[0];
        for(int z=1;z<=len-1;z++){
            if(count>max)
                max=count;
        }
        System.out.println(max);
        System.out.println("The character that appears the most number of times is "  +arr[max]);
    }
}

我得到计数​​来显示每个字符在字符串中出现的次数，我无法将它与数组中的其余元素进行比较。

出现的次数存储在数组“arr[]”中，如何找到该数组中最大的整数？另外，如何显示出现次数最多的角色？

代码的逻辑在之后不起作用，

  int max=arr[0];

关于该做什么有什么想法吗？

Answer 1

    String sent = "asdAdFfaedfawghke4";//s.nextLine();      
    int length = sent.length();
    char frequentChar = ' ';
    int maxLength = 0;
    for (int i = 0; i < length; i++) {
        char currentChar = sent.charAt(0);
        sent = sent.replaceAll(currentChar + "", "");//remove all charactes from sent
        if (maxLength < (length - sent.length())) {
            frequentChar=currentChar;
            maxLength = length - sent.length();
        }
        System.out.println("Char : " + currentChar + " Occurance " + (length - sent.length()));
        length = sent.length();
    }
    System.out.println("Max Occurance : " + maxLength);

输出:

Char : a Occurance 3
Char : s Occurance 1
Char : d Occurance 3
Char : A Occurance 1
Char : F Occurance 1
Char : f Occurance 2
Char : e Occurance 2
Frequent Char : a
Max Occurance : 3