我试图从 SQL 数据库中选择日期并将其放入 JTable 中,但我不断收到错误:
'AWT-EventQueue-0" java.lang.ArrayIndexOutOfBoundsException: 0'
不太清楚为什么。这是我的代码:
table = new JTable();
try {
Connection MyConn = null;
Statement statement = null;
ResultSet rs = null;
Class.forName("com.mysql.jdbc.Driver");
MyConn = DriverManager.getConnection("jdbc:mysql:"
+ "//localhost/eventbooking", "root", "Passw0rd");
statement = MyConn.createStatement();
rs = statement.executeQuery("SELECT * FROM `events` WHERE `Date Of Event` = '30/03/2014'");
int i=0;
while (rs.next()) {
Object a = rs.getString("Date Of Event");
Object b = rs.getString("Tickets Available");
Object c = rs.getString("Price Of Event");
Object d = rs.getString("Start Time");
table.setRowSorter(null);
table.getModel().setValueAt(a, i, 0 );
table.getModel().setValueAt(b, i, 1);
table.getModel().setValueAt(c, i, 2);
table.getModel().setValueAt(d, i, 3);
EventDiary.this.add(table);
System.out.println(i);
i++;
}
最佳答案
问题是您正在创建一个默认的 JTable,它具有一个由 Vector 组成的 TableModel,其中没有任何元素。然后,您尝试将元素设置在所述 vector 的索引 0 处,该元素此时不存在,瞧:您遇到了问题。
例如:
JTable table = new JTable();
table.getModel().setValueAt("i", 0, 0);
System.out.println(table);
结果:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0 >= 0
at java.util.Vector.elementAt(Vector.java:470)
at javax.swing.table.DefaultTableModel.setValueAt(DefaultTableModel.java:665)
at com.stackoverflow.answer.JTableTest.main(JTableTest.java:9)
例如以下内容:
JTable table = new JTable(1, 1);
table.getModel().setValueAt("i", 0, 0);
System.out.println(table);
结果:
javax.swing.JTable[,0,0,0x0,invalid,alignmentX=0.0,alignmentY=0.0,border=,flags=251658568,maximumSize=,minimumSize=,preferredSize=,autoCreateColumnsFromModel=true,autoResizeMode=AUTO_RESIZE_SUBSEQUENT_COLUMNS,cellSelectionEnabled=false,editingColumn=-1,editingRow=-1,gridColor=javax.swing.plaf.ColorUIResource[r=255,g=255,b=255],preferredViewportSize=java.awt.Dimension[width=450,height=400],rowHeight=16,rowMargin=1,rowSelectionAllowed=true,selectionBackground=com.apple.laf.AquaImageFactory$SystemColorProxy[r=44,g=93,b=205],selectionForeground=com.apple.laf.AquaImageFactory$SystemColorProxy[r=255,g=255,b=255],showHorizontalLines=true,showVerticalLines=true]
因此,如果您想坚持自己的做事方式,您需要事先添加行和列。
另一种方法是:
JTable table = new JTable();
DefaultTableModel model = (DefaultTableModel) table.getModel();
model.addColumn("id");
model.addColumn("name");
Object[] row = new Object[2];
row[0] = 1;
row[1] = "John";
model.addRow(row);
row = new Object[2];
row[0] = 2;
row[1] = "Jack";
model.addRow(row);
for (int i = 0; i < model.getRowCount(); i++) {
for (int j = 0; j < model.getColumnCount(); j++) {
System.out.println("column: " + model.getColumnName(j) + ", row #" + i + ", value: " + model.getValueAt(i, j));
}
}
结果:
column: id, row #0, value: 1
column: name, row #0, value: John
column: id, row #1, value: 2
column: name, row #1, value: Jack
关于java - AWT-EventQueue-0“java.lang.ArrayIndexOutOfBoundsException : 0 error for JTable,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22133871/