java - 为什么方法会更改 boolean 数组参数?

标签 java arrays recursion boolean path-finding

我有一个类(class),用于寻找穿过基本迷宫的路径。迷宫连同起始位置和结束位置一起传递到路径。我使用递归来查找点之间的路径。该路径以 boolean 数组的形式返回。由于某种原因,传递给 Path() 的初始迷宫发生了变化。因此,我尝试制作迷宫数组的副本以避免更改任何值,但它仍然不起作用。

为什么 path() 对 open[][] 进行更改?可能是 C 编程让我困惑。

public static boolean[][] path(boolean[][] open, 
                               int start_i, int start_j, 
                               int end_i, int end_j) 
{
    int n = open.length;
    boolean[][] openCopy = new boolean[n][n]; //make a copy of open

    for(int i = 0; i < n; i++)
    {
        for(int j = 0; j < n; j++)
        {
            openCopy[i][j] = open[i][j]; 
        }
    } 
    return findPath(openCopy, start_i, start_j, end_i, end_j);
}

public static boolean[][] findPath(boolean[][] openCopy, int start_i, int start_j, int end_i, int end_j) 
{
    boolean[][] path = new boolean[openCopy.length][openCopy[0].length];

    if(openCopy[start_i][start_j] == false) //return false if current position is not open
        return path;
    else
        openCopy[start_i][start_j] = false;  //make current position false if not (to prevent infinite backtracking)

    if(start_i == end_i && start_j == end_j) //if end found return true
    {
        path[start_i][start_j] = true;
        return path;
    }

    path = findPath(openCopy, start_i+1, start_j, end_i, end_j); // Move North
    path = findPath(openCopy, start_i, start_j+1, end_i, end_j); // Move East
    path = findPath(openCopy, start_i-1, start_j, end_i, end_j); // Move South
    path = findPath(openCopy, start_i, start_j-1, end_i, end_j); // Move West

    return path;
}

最佳答案

事实并非如此,我知道这可能不是该方法完全“合适”的输入,但它证明了这一点:

public class MainForm {


public static void main(String[] args) {
    boolean[][] array = new boolean[][] {{false, false, true, false, false, false}, 
            {false, false, true, false, false, false}, 
            {false, false, true, false, false, false}, 
            {false, false, true, false, false, false}};

    boolean[] [] another = path(array, 0, 0, 3, 5);

    for (boolean[] bArray : array) {
        for (boolean b : bArray) {
            System.out.println(b);
        }
    }
    System.out.println("***********************");
    for (boolean[] bArray : another) {
        for (boolean b : bArray) {
            System.out.println(b);
        }
    }
}

public static boolean[][] path(boolean[][] open, int start_i, int start_j, int end_i, int end_j) {
    int n = open.length;
    boolean[][] openCopy = new boolean[n][n]; // make a copy of open

    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            openCopy[i][j] = open[i][j];
        }
    }
    return findPath(openCopy, start_i, start_j, end_i, end_j);
}

public static boolean[][] findPath(boolean[][] openCopy, int start_i, int start_j, int end_i, int end_j) {
    boolean[][] path = new boolean[openCopy.length][openCopy[0].length];

    if (openCopy[start_i][start_j] == false) // return false if current position is not open
        return path;
    else
        openCopy[start_i][start_j] = false; // make current position false if not (to prevent infinite backtracking)

    if (start_i == end_i && start_j == end_j) // if end found return true
    {
        path[start_i][start_j] = true;
        return path;
    }

    path = findPath(openCopy, start_i + 1, start_j, end_i, end_j); // Move North
    path = findPath(openCopy, start_i, start_j + 1, end_i, end_j); // Move East
    path = findPath(openCopy, start_i - 1, start_j, end_i, end_j); // Move South
    path = findPath(openCopy, start_i, start_j - 1, end_i, end_j); // Move West

    return path;
}
}

输出

false
false
true
false
false
false
false
false
true
false
false
false
false
false
true
false
false
false
false
false
true
false
false
false
***********************
false
false
false
false
false
false
false
false
false
false
false
false
false
false
false
false

显然,返回的数组和传递给path()的数组内容不同,而原始数组的原始值保持不变。我认为问题出在您的应用程序的其他地方。

关于java - 为什么方法会更改 boolean 数组参数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22414624/

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