Java 最小最大值

Question

一切正常，我只需要输出表示降雨量最高/最低的季度，而不是实际值。我不确定如何将季度和值联系在一起，以便输出为季度 1、2、3 或 4。

import java.util.Scanner;

public class rainfall
{
   public static void main(String[] args) 
   { 
      Scanner scan = new Scanner(System.in); 
      double[] rainfall = new double[4]; 
      double totalRainfall = 0.0; 
      double max = 0, min = 0;


      for (int i=0; i < 4; i++) 
      { 
         System.out.print("Enter rainfall for quarter " + (i+1) + ": "); 
         rainfall[i] = scan.nextDouble(); 
         totalRainfall += rainfall[i]; 
         if (i == 0)
         {
            max = min = rainfall[i];
         }

         {
            if (rainfall[i] > max)
               max = rainfall[i];
            else if (rainfall[i] < min)
               min = (i + 1);
            //min = rainfall[i];     
         }
     }

   System.out.println("Total rainfall = "+totalRainfall); 
   System.out.println("Average rainfall = "+(totalRainfall / 4.0)); 
   System.out.println("Max quarter rainfall = "+ max);
   System.out.println("Min quarter rainfall = " + min);

   //System.out.println("Max quarter rainfall = "+ maxQuarter);
   //System.out.println("Min quarter rainfall = " + minQuarter);

   }//end main 
}//end class

Answer 1

仅存储索引而不是值:

if (rainfall[i] > rainfall[max])
    max = i;
else if (rainfall[i] < rainfall[min])
    min = i;

System.out.println("Max quarter rainfall = " + max + 1);
System.out.println("Min quarter rainfall = " + min + 1);