在 SQL Server 中,我使用下面的查询将特定目录(例如 z:) 中的所有“.jpg”文件名加载到表中。
我想知道是否有一种方法可以根据 Created Date 而不是 Modified Date 在 Windows 命令提示符下加载文件。以下查询仅在执行 xp_cmdshell
时适用于修改日期。
-- Create the table to store file list
CREATE TABLE myFilesTable (myFileID INT IDENTITY, myFileName NVARCHAR(256))
-- Insert file list from directory to SQL Server
DECLARE @Command varchar(1024) = 'z: & forfiles /m *.jpg /s /d 07/16/2015 /c "cmd /c echo @fdate @ftime @path"'
INSERT INTO myFilesTable
EXEC MASTER.dbo.xp_cmdshell @Command
-- Check the list
SELECT * FROM myFilesTable
GO
变量 @Command
中的 07/16/2015
是修改日期。显然命令 forfiles
没有根据 Created Date 过滤文件的线索。
下面是上面给出的查询的一些结果,其中文件名以修改日期为前缀。
myFileID | myFileName
----------------------
1 | NULL
2 | 8/18/2015 11:13:08 AM "Z:\LDB1 App Export\Top Star_Aluminium Frames & Furniture (B)-31267.jpg"
3 | 8/19/2015 5:44:41 PM "Z:\LDB2 App Export\Soe Tint_Hardware Merchants & Ironmongers-31435.jpg"
4 | 8/19/2015 10:37:13 AM "Z:\Cover App Export\Taw Win Tun_Electrical Goods Sales & Repairing (A) -31382.jpg"
5 | 8/24/2015 10:34:33 AM "Z:\CP1 App Export\Thiri May_Fabric Shop (B)-30646.jpg"
6 | 8/17/2015 10:08:39 AM "Z:\CP2 App Export\Ko Tin Aung_Building Materials (B)-31300.jpg"
我也尝试过将 dir
命令与时间字段 /t:c
(创建时间)一起使用,例如
EXEC MASTER.dbo.xp_cmdshell 'dir z: *.jpg /t:c /s'
它为我提供了创建日期,但它向我显示了以下与预期不同的结果。我想要具有完整路径/目录名称的文件名,如上一个结果所示。
myFileID | myFileName
----------------------
1 | Volume in drive Z is Publication
2 | Volume Serial Number is 3EF0-5CE4
3 | NULL
4 | Directory of Z:\
5 | NULL
6 | 07/28/2015 06:41 PM <DIR> .
7 | 07/28/2015 07:06 PM <DIR> ..
8 | 03/05/2015 11:42 AM <DIR> LDB1 App Export
9 | 03/05/2015 05:31 PM <DIR> LDB2 App Export
10 | 0 File(s) 0 bytes
11 | NULL
12 | Directory of Z:\LDB1 App Export
13 | NULL
14 | 03/05/2015 11:42 AM <DIR> .
15 | 07/28/2015 06:41 PM <DIR> ..
16 | 07/28/2015 06:49 PM 2,981,526 Kyaw Phay_Dental Equipment (A)-30998.jpg
17 | 08/31/2015 03:10 PM 3,126,629 Venus_Fashion Shops-31438.jpg
18 | 07/28/2015 06:49 PM 3,544,247 Marvellous_Tourism Services-30986.jpg
... | ...
预期的结果应该如下所示,
myFileID | CreatedDate | myFileName
----------------------------------------------
1 | 8/10/2015 11:24:16 AM | "Z:\LDB1 App Export\Top Star_Aluminium Frames & Furniture (B)-31267.jpg"
2 | 8/10/2015 11:24:27 AM | "Z:\LDB2 App Export\Soe Tint_Hardware Merchants & Ironmongers-31435.jpg"
3 | 8/12/2015 10:05:22 AM | "Z:\Cover App Export\Taw Win Tun_Electrical Goods Sales & Repairing (A) -31382.jpg"
4 | 8/12/2015 10:05:22 AM | "Z:\CP1 App Export\Thiri May_Fabric Shop (B)-30646.jpg"
5 | 8/12/2015 10:05:22 AM | "Z:\CP2 App Export\Ko Tin Aung_Building Materials (B)-31300.jpg"
任何帮助将不胜感激:)
最佳答案
这是一种解析 DIR 命令输出的方法:
--Create the table to store file list
CREATE TABLE myFilesTable (myFileID INT IDENTITY, myFileCreateDate datetime, myFileName NVARCHAR(256))
--Create temporary table to store output of DIR command
CREATE TABLE #DirectoryOutput (LineID INT IDENTITY, LineData NVARCHAR(256))
--Insert file list from directory to SQL Server
DECLARE @Command varchar(1024) = 'dir z: *.jpg /t:c /s'
INSERT INTO #DirectoryOutput
EXEC MASTER.dbo.xp_cmdshell @Command
--Check the list
insert into myFilesTable
select
convert(Datetime,(left(LineData, 20))) CreateDate,
FilePath2.FilePath + '\' + right(LineData,len(LineData)-39) Filename
from #DirectoryOutput
cross apply
(
select Max(LineID) LineID
from #DirectoryOutput FilePaths
where LEFT(LineData,14)=' Directory of '
and FilePaths.LineID < #DirectoryOutput.LineID
) FilePath1
join
(
select LineID, RIGHT(LineData, LEN(LineData)-14) FilePath
from #DirectoryOutput FilePaths
where LEFT(LineData,14)=' Directory of '
) FilePath2
on FilePath1.LineID = FilePath2.LineID
where ISDATE(left(LineData, 20))=1
order by 1
select * from myFilesTable
GO
关于sql-server - 如何通过 SQL Server xp_cmdshell 在 Windows 命令 shell 中根据创建日期加载文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32293517/