我正在开发一款两人乒乓球游戏,希望用一根手指控制每只球棒。然而,我的问题是它一次只响应一根手指在屏幕上。整个游戏在一个 View 中运行。首先,我检查指针是否处于“Activity ”状态,然后检查它是否出现在屏幕的顶部或底部,然后再移动相应的 bat 。除了只有一次触摸记录外,它工作正常。我的方法代码如下:
// variables
int _touchY = (int) event.getY();
boolean isTopSide = true;
// test if motionEvent was on the top or bottom of the screen
if (SCREEN_HEIGHT / 2 - _touchY < 0) {
isTopSide = false;
}
switch (event.getActionMasked()) {
case MotionEvent.ACTION_DOWN:
_activePointer = event.getPointerId(0);
break;
case MotionEvent.ACTION_MOVE:
if(_activePointer != INVALID_POINTER_ID) {
if (isTopSide) { // top bat
_topBat.moveBat(event);
} else { // bottom bat
_botBat.moveBat(event);
}
}
if(_newPointer != INVALID_POINTER_ID){
if (isTopSide) { // top bat
_topBat.moveBat(event);
} else { // bottom bat
_botBat.moveBat(event);
}
}
break;
case MotionEvent.ACTION_UP:
if(_activePointer != INVALID_POINTER_ID){
_activePointer = INVALID_POINTER_ID;
}
break;
case MotionEvent.ACTION_CANCEL:
_activePointer = INVALID_POINTER_ID;
break;
case MotionEvent.ACTION_POINTER_UP:
int pointerIndex = event.getActionIndex();
int pointerId = event.getPointerId(pointerIndex);
if(pointerId == _activePointer){
_activePointer = INVALID_POINTER_ID;
}
case MotionEvent.ACTION_POINTER_DOWN:
int newPointerIndex = event.getActionIndex();
_newPointer = event.getPointerId(newPointerIndex);
break;
}
相关全局代码
// touched
private static final int INVALID_POINTER_ID = -1;
private int _activePointer = INVALID_POINTER_ID;
private int _newPointer = INVALID_POINTER_ID;
最佳答案
为什么您只看到单个指针的值的主要问题是因为没有任何参数的 event.getY()
为您提供了第一个指针索引的位置,即使该指针实际上移动的是第二个指针。
MotionEvent 类包含所有 Activity 指针的坐标。
如果您想获取第二个指针的位置,您需要调用event.getY(1)
。
您可能希望循环遍历所有 Activity 点,通过 event.getPointerCount()
获取总计数,然后相应地发送事件。
关于java - Android MultiTouch 仅适用于一根手指,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24026296/