我要重修这门课,有一份家庭作业,我遇到的问题是我对解决方案的思考过多。我必须创建一个程序将四位数转换为单词。
(示例:1134 变为“一一三四”)
我有一个基本代码,但它又笨重又难看。我也只允许使用基本的 if 和 switch 语句,我们也必须使用 switch 语句。
我是不是想多了?我不知道如何使这段代码更短,我只想使用一个没有 while 循环的 switch 语句。这是否可能,或者是否已经尽可能短了。
这是我的代码。
import java.util.Scanner;
public class NumberToWords {
public static void main(String[] args) {
//Set up scanner.
Scanner kb = new Scanner(System.in);
//Ask for a 4 digit integer.
System.out.println("Enter a 4 digit number.");
//Store 4 digit number into a variable
int number = kb.nextInt();
//Seperate number into digits.
int digit4 = number%10;
number = number/10;
int digit3 = number%10;
number = number/10;
int digit2 = number%10;
number = number/10;
int digit1 = number%10;
number = number/10;
//Set up a switch statement to read through the number.
switch (digit1)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit2)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit3)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit4)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
}
}
最佳答案
首先,编写一个将单个数字转换为单词的方法。比如,
private static String digitToWord(char ch) {
switch(ch) {
case '0': return "Zero";
case '1': return "One";
case '2': return "Two";
case '3': return "Three";
case '4': return "Four";
case '5': return "Five";
case '6': return "Six";
case '7': return "Seven";
case '8': return "Eight";
case '9': return "Nine";
}
return "Unknown (" + ch + ")";
}
然后你就可以得到你的int
的String
值。并从该String
中获取四个字符。比如,
int number = kb.nextInt();
String str = String.format("%04d", number);
StringBuilder sb = new StringBuilder();
sb.append(digitToWord(str.charAt(0)).append(' ');
sb.append(digitToWord(str.charAt(1)).append(' ');
sb.append(digitToWord(str.charAt(2)).append(' ');
sb.append(digitToWord(str.charAt(3));
System.out.println(sb.toString());
或者,
String str = String.format("%04d", kb.nextInt());
System.out.printf("%s %s %s %s%n", digitToWord(str.charAt(0)),
digitToWord(str.charAt(1)), digitToWord(str.charAt(2)),
digitToWord(str.charAt(3)));
关于java - Java 中的数字到单词的转换,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25924949/