是否可以在 Spring XML 上下文中定义几个具有相同属性集的 bean?
示例
<bean id="bean1" class="com.my.company.model.MyProcedureBean">
<property name="name" value="val1"/>
<property name="pre">
<list>
<ref bean="Y00"/>
<ref bean="YNT"/>
<ref bean="YAB"/>
</list>
</property>
<property name="post">
<list>
<ref bean="YIO"/>
<ref bean="YC1"/>
</list>
</property>
<property name="plain">
<list>
<ref bean="YA3"/>
<ref bean="YP4"/>
<ref bean="YA5"/>
</list>
</property>
</bean>
<bean id="bean2" class="com.my.company.model.MyProcedureBean">
// DO NOT WANT TO DUPLICATE ALL PROPERTIES HERE AS AT **bean1**
</bean>
最佳答案
将一个bean的Abstract属性设置为true,然后定义其他bean,其父属性等于该抽象bean! 像这样
<bean id="parentBean" class="xxx" abstract="true">
<property name="..." value="..." />
<property name="..." value="..." />
<property name="..." value="..." />
</bean>
<bean id="bean1" parent="parentBean">
</bean>
<bean id="bean2" parent="parentBean">
</bean>
关于java - 声明具有相同属性的 bean,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26917745/