java - 在 android 中使用文本框和按钮

Question

这是我的第一个应用程序，我遇到了问题。每次我点击按钮它就会崩溃。该应用程序的想法是使用三个文本框中的三个数字进行简单计算，并将结果输出到另一个文本框中。这是我的代码。

package com.example.jeehbs.myfirstapp;

import android.app.Fragment;
import android.support.v7.app.ActionBarActivity;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.EditText;
import android.widget.TextView;


public class MainActivity extends ActionBarActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
}


@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.menu_main, menu);
    return true;
}

@Override
public boolean onOptionsItemSelected(MenuItem item) {
    // Handle action bar item clicks here. The action bar will
    // automatically handle clicks on the Home/Up button, so long
    // as you specify a parent activity in AndroidManifest.xml.
    int id = item.getItemId();

    //noinspection SimplifiableIfStatement
    if (id == R.id.action_settings) {
        return true;
    }

    return super.onOptionsItemSelected(item);
}

public void mathIt(View view){
    EditText price = (EditText) findViewById(R.id.price);
    EditText oz = (EditText) findViewById(R.id.oz);
    EditText amount = (EditText) findViewById(R.id.amount);
    int p = Integer.parseInt(price.getText().toString());
    int o = Integer.parseInt(oz.getText().toString());
    int a = Integer.parseInt(amount.getText().toString());
    int result = (a*o)/p;
    TextView resultView = (TextView) findViewById(R.id.resultView);
    resultView.setText(result);
}
}

Answer 1

setText 采用字符串参数而不是整数，尝试 resultView.setText(String.valueOf(result));。整数参数是字符串资源的引用R.string.string_name