java - Android:将 Parcelable 对象传递给另一个 Activity 时出错

标签 java android arraylist parcelable

我正在尝试将一个对象从我的 MainActivity 传递到另一个对象。它有一个 ArrayList 类型的属性,该属性已更改,我不知道为什么。在 MainActivity 中,我使用对象的 toStringSystem.out.println() 来查看他拥有什么,我可以看到以下内容:

Incidente{name='Farola fundida', type='sin luz', street='falsa', streetNumber=123, city='Bilbao', contacts=[alguien1, alguien2]}

但是,当我在其他 Activity 中收到它时,我又做了一个 System.out.println() 并得到了这个:

Incidente{name='Farola fundida', type='sin luz', street='falsa', streetNumber=123, city='Bilbao', contacts=[, null]}

你能告诉我我做错了什么吗?

我的类(class)Incidente代码是这样的:

public class Incidente implements Parcelable{

    String name;
    String type;
    String street;
    int streetNumber;
    String city;
    ArrayList<String> contacts;

    public Incidente(String name, String type, String street, int streetNumber, String city, ArrayList<String> contacts) {
        this.name = name;
        this.type = type;
        this.street = street;
        this.streetNumber = streetNumber;
        this.city = city;
        this.contacts = contacts;
    }


    protected Incidente(Parcel in) {
        name = in.readString();
        type = in.readString();
        street = in.readString();
        streetNumber = in.readInt();
        city = in.readString();
        contacts = in.createStringArrayList();
    }

    public static final Creator<Incidente> CREATOR = new Creator<Incidente>() {
        @Override
        public Incidente createFromParcel(Parcel in) {
            return new Incidente(in);
        }

        @Override
        public Incidente[] newArray(int size) {
            return new Incidente[size];
        }
    };

    @Override
    public int describeContents() {
        return 0;
    }

    @Override
    public void writeToParcel(Parcel dest, int flags) {
        dest.writeString(name);
        dest.writeString(type);
        dest.writeString(street);
        dest.writeInt(streetNumber);
        dest.writeString(city);
        dest.writeList(contacts);
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getType() {
        return type;
    }

    public void setType(String type) {
        this.type = type;
    }

    public String getStreet() {
        return street;
    }

    public void setStreet(String street) {
        this.street = street;
    }

    public int getStreetNumber() {
        return streetNumber;
    }

    public void setStreetNumber(int streetNumber) {
        this.streetNumber = streetNumber;
    }

    public String getCity() {
        return city;
    }

    public void setCity(String city) {
        this.city = city;
    }

    public ArrayList<String> getContacts() {
        return contacts;
    }

    public void setContacts(ArrayList<String> contacts) {
        this.contacts = contacts;
    }

    @Override
    public String toString() {
        return "Incidente{" +
                "name='" + name + '\'' +
                ", type='" + type + '\'' +
                ", street='" + street + '\'' +
                ", streetNumber=" + streetNumber +
                ", city='" + city + '\'' +
                ", contacts=" + contacts +
                '}';
    }

    public boolean equals (Incidente obj2)
    {

        if(this.getName().equals(obj2.getName()))
        {
            if(this.getType().equals(obj2.getType()))
            {
                if(this.getStreet().equals(obj2.getStreet()))
                {
                    if(this.getStreetNumber()== obj2.getStreetNumber())
                    {
                        if(this.getCity().equals(obj2.getStreetNumber()))
                        {
                            if(this.getContacts().equals(obj2.getContacts()))
                            {
                                return true;
                            }
                        }
                    }
                }
            }
        }
        return false;
    }
}

这就是我发送对象的方式:

ArrayList<String> arrContactos=new ArrayList<String>();
arrContactos.add("alguien1");
arrContactos.add("alguien2");
Incidente inci = new Incidente("Farola fundida", "sin luz", "falsa", 123, "Bilbao", arrContactos);

Intent i = new Intent(this, DetalleIncidenteActivity.class);
i.putExtra("objeto",inci);

这就是我收到它的方式:

incidente=getIntent().getExtras().getParcelable("objeto");

最佳答案

来自 createStringArrayList 的文档:

Read and return a new ArrayList containing String objects from the parcel that was written with writeStringList(List) at the current dataPosition().

因此,根据文档,您应该使用 writeStringList(List) 而不是 writeList

关于java - Android:将 Parcelable 对象传递给另一个 Activity 时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33517886/

相关文章:

javascript - BottomNavigationView 的菜单未选择

java - 数字 OCR。用 Hu 不变矩分类

android - 如何在 Android 中制作自定义 ANR 对话框而不是 android ANR 对话框

java - 为什么任何标记为 final 的类都不允许编译器去虚拟化方法调用

java - 如何刷新 View

android - 如何从 Unity Player 返回到之前运行的 Android Activity?

python - 如何将列表与常见元素合并,其中这些元素本身是列​​表/元组?

java - 从文本文件读取并创建对象数组 Java

java - 未能使我的 ArrayList 成为线程安全的。线程中的异常 "main"java.lang.ClassCastException : What is wrong?

java - 2 个 JButtons 2 GUI