java - 如何在java中显示正确的数组

Question

我创建了一个 Java 程序，我想显示统计信息。 当用户输入1时，它是单一的。当用户输入2时，它是一对。当用户输入 3 时，它是一个 3 的家庭。

示例如下:

Scanner sc = new Scanner(System.in);

System.out.print("Enter group #1: ");
int g1 = sc.nextInt();
sc.nextLine();

System.out.print("Enter group #2: ");
int g2 = sc.nextInt();
sc.nextLine();

System.out.print("Enter group #3: ");
int g3 = sc.nextInt();
sc.nextLine();

System.out.print("Enter group #4: ");
int g4 = sc.nextInt();
sc.nextLine();

int[] numbers = {g1,g2,g3,g4};
int[] count = new int[] { 0, 0, 0};

String[] category = new String[]{"Single", "Couple","Family of 3"};
//String[][] category = new String[][] {{"Single"}, {"Couple"}, {"Family of 3"}};
String a = Arrays.toString(category).replaceAll("[\\[\\]]", "");
for (int i = 0; i < numbers.length; i++) {
    count[numbers[i] - 1]++;
}

System.out.println("");
System.out.println("Statistic: ");

for (int i=2; i <count.length; i++)
{
    System.out.println(a + " : " + count[i]);
}

但是显示太奇怪了。可以帮忙吗？

结果:

run:
Enter group #1: 1
Enter group #2: 1
Enter group #3: 1
Enter group #4: 1

Statistic: 
Single, Couple, Family of 3 : 4
Single, Couple, Family of 3 : 0
Single, Couple, Family of 3 : 0
BUILD SUCCESSFUL (total time: 4 seconds)

正确的结果应该是:

run:
Enter group #1: 1
Enter group #2: 1
Enter group #3: 1
Enter group #4: 1

Statistic: 
Single : 4
Couple: 0
Family of 3 : 0

Answer 1

而不是

for (int i=2; i <count.length; i++)
{
    System.out.println(a + " : " + count[i]);
}

应该是

for (int i=0; i <count.length; i++)
{
    System.out.println(category[i] + " : " + count[i]);
}

并删除变量a。