java - 如何以正确的方式将java对象写入firebase？

Question

我正在尝试将数据写入 Firebase，这真的很神奇，并且在某种程度上让一切看起来都像魔法，但我很难理解它处理数据和排列数据的方式，我已经阅读了文档，并且我仍然无法成功获得我想要的东西(或者可能只是感到失落)。 我现在有一个 Client java 类，它有两个参数，我想编写 名字和姓氏

package com.example.android.bookkeepingapp;

import com.google.firebase.database.Exclude;

 import java.util.HashMap;
 import java.util.Map;

public class Client {

//client information
private static long clientId = 0;
private String firstName;
private String lastName;

private String companyName;

private String address;
private String email;
private String phoneNumber;

public Client()
{}

public Client(String firstName, String mLastName)
{
    //take the last value and increase it by one
    clientId = clientId + 1;
    this.firstName = firstName;
    this.lastName = getmLastName();
}

public Client(String companyName)
{
    this.companyName = companyName;
}

public String getmAddress() {
    return this.address;
}

public String getmCompanyName() {
    return this.companyName;
}

public String getmEmail() {
    return this.email;
}

public String getmFirstName() {
    return this.firstName;
}

public String getmLastName() {
    return this.lastName;
}

public static long getClientId() {
    return clientId;
}

public String getmPhoneNumber() {
    return this.phoneNumber;
}

public void setmAddress(String address) {
    this.address = address;
}

public void setmCompanyName(String companyName) {
    this.companyName = companyName;
}

public void setmEmail(String email) {
    this.email = email;
}

public void setmFirstName(String firstName) {
    this.firstName = firstName;
}

public void setmLastName(String lastName) {
    this.lastName = lastName;
}

public void setmPhoneNumber(String phoneNumber) {
    this.phoneNumber = phoneNumber;
}

/**
 * Map will use for writing the items to the database.
 * @return
 */
@Exclude
public Map<String, Object> toMap() {
    HashMap<String, Object> result = new HashMap<>();
    result.put("firstName", firstName);
    result.put("lastName", lastName);
    /*result.put("companyName" ,companyName);
    result.put("address" ,address);
    result.put("email" ,email);
    result.put("phoneNumber" ,phoneNumber);*/
    return result;
}

}

我想要实现的是在主数据库中有一个名为 client 的分支

 mClientDatabaseReference = mFirebaseDatabase.getReference().child("client");

这是添加新用户时发生的情况

// create new client at /track-my-business/client/
                    final String key =FirebaseDatabase.getInstance().getReference().push().getKey();

                    // get user input and set it to result
                    // edit text
                    Client client = new Client(firstNameEditText.getText().toString(),
                            lastNameEditText.getText().toString());

                    Map<String, Object> clientValues = client.toMap();

                    Map<String, Object> childUpdates = new HashMap<>();

                    childUpdates.put(key, clientValues);
                    FirebaseDatabase.getInstance().getReference().updateChildren(childUpdates);

简单来说，执行上述代码后数据如下所示:

但这就是我想要的

我希望客户端的firstName和lastName都写入同一个键值中，当我执行代码时，只有firstName被成功写入。

Answer 1

updateChildren() 用于当您想要更新某个字段时。

要发送数据，您可以简单地执行以下操作:

DatabaseReference ref=FirebaseDatabase.getInstance().getReference().child("client").push();
ref.child("firstName").setValue(fname);
ref.child("LastName").setValue(lname);

然后你会得到这个:

client
   pushid
     firstName: fname
     LastName:lname
   pushid
      //data of other client