java - 检查字符串是否包含列表中的任何字符串

Question

我对 java 很陌生，目前陷入困境，不知道如何继续。

我想要做的是检查字符串是否包含单词列表中的任何单词，如果是则输出它们。

在我的例子中，所有字符串都会有类似的文本(例如 5 分钟):

Set timer to five minutes

或者这个:

Timer five minutes

这是我当前的代码，其中包含一些我正在尝试执行的操作:

import java.util.stream.Stream; 

class GFG { 

// Driver code 
public static void main(String[] args) 
{ 

String example = Set timer to five minutes

    Stream<String> stream = Stream.of(("Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten") //The stream/array would be much bigger since I want to cover every number till 200 

//Now I thought I can use stream filter to check if example contains the word Timer and any of the words of the Stream and if it does I want to use the output to trigger something else

    if(stream.filter(example -> example .contains(NOTSUREWHATTOPUTHERE))) {
       //If detected that String contains Timer and Number, then create timer 
    } 
} 

有人可以给我一些建议/帮助吗？

问候

Answer 1

你可以这样做:

String[] words = { "Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten" };

String example = "Set timer to five minutes";

String exLower = example.toLowerCase();
if (Stream.of(words).anyMatch(word -> exLower.contains(word.toLowerCase()))) {
    //
}

该代码至少会正确检查，即使单词具有不同的大写/小写，但如果文本中嵌入了另一个单词，例如，则该代码会失败。文本 "stone" 将匹配，因为找到了 "one"。

要解决这个问题，“最简单”的方法是将单词列表转换为正则表达式。

String[] words = { "Timer", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten" };

String example = "Set timer to five minutes";

String regex = Stream.of(words).map(Pattern::quote)
        .collect(Collectors.joining("|", "(?i)\\b(?:", ")\\b"));
if (Pattern.compile(regex).matcher(example).find()) {
    //
}