我得到这个 JSON 字符串:
[
{
"id": 135,
"date": "2013-08-30 19:00:29",
"timestamp": "2013-08-30 19:00:29",
"lat": "54.328274",
"long": "-2.747215",
"strap": "annual International Festival of Street Arts",
"link": "http://dev.website.co.uk//?p=135",
"title": "Title"
}
]
我确信这是正确的 JSON 语法(在 iOS 应用程序中工作正常),但是当解析为 JSONObject 时,它会捕获错误。 Java:
public static JSONObject getJSONfromURL(String url){
//initialize
InputStream is = null;
String result = "";
JSONObject jArray = null;
//http post
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
} catch (Exception e) {
Log.e("log_tag", "Error in http connection "+e.toString());
}
//convert response to string
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
} catch (Exception e) {
Log.e("log_tag", "Error converting result "+e.toString());
}
//try parse the string to a JSON object
try {
Log.d("log_tag", "jresult: " + result + "finish");
jArray = new JSONObject(result);
} catch (JSONException e) {
Log.e("log_tag", "Error parsing data "+e.toString());
}
return jArray;
}
JSON 中是否有错误?
最佳答案
[
表示json数组节点
{
表示json对象节点
JSONArray jArray = new JSONArray(result);
return jArray;
此外,您可以使用一个 try block 而不是多个。
关于java - JSONObject 未正确创建(可能是 JSON 格式错误?),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17366459/