我正在编写一个代码,从用户那里获取卡片并将其放入一副牌中,卡片的值(value)取决于数字,例如1 然后 5 将是红心 5,3 然后 13 将是黑桃 K。如果卡插入正确,它应该返回 true,如果没有插入,它应该抛出异常,它应该检查牌组中的空间,如果没有,它应该返回 false,最后,如果卡已经插入,它应该返回 false。错误在评论中。
import java.util.Scanner;
public static void main(String[] args){ //red underline error on void saying "syntax error token", under the second bracket of String[] and on the last bracket after args.
private static addCards(){
String suit[] = {"Hearts", "Diamonds", "Spades", "Clubs"};
String value[] = {"ZZZZ", "Ace", "2", "3", "4", "5", "6",
"7", "8", "9", "10", "Jack", "Queen", "King"};
String[] card = new String[52];
String[] newSuit = new String[4];
Scanner input = new Scanner(System.in); //it says it expects a { instead of the semicolon here.
for (int i = 0; i < 52; i++){
System.out.println("Please enter a suit");
int inputSuit = input.nextInt();
check = false;
if(inputSuit = 1 || 2 || 3 || 4 ){
check = true;
}
System.out.println("Please enter a card");
int inputValue = input.nextInt();
check1 = false;
if(inputValue = 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 || 9 || 10 || 11 || 12 || 13){
check1 = true;
}
try{
check = true;
check1 = true;
}
catch(card exception){
ex.printStackTrace();
System.exit(1);
}
switch (inputSuit) {
case 0: newSuit[i] = suit[0]; break;
case 1: newSuit[i] = suit[1]; break;
case 2: newSuit[i] = suit[2]; break;
case 3: newSuit[i] = suit[3]; break;
}
switch (inputValue) {
case 1: card[i] = value[1]; break;
case 2: card[i] = value[2]; break;
case 3: card[i] = value[3]; break;
case 4: card[i] = value[4]; break;
case 5: card[i] = value[5]; break;
case 6: card[i] = value[6]; break;
case 7: card[i] = value[7]; break;
case 8: card[i] = value[8]; break;
case 9: card[i] = value[9]; break;
case 10: card[i] = value[10]; break;
case 11: card[i] = value[11]; break;
case 12: card[i] = value[12]; break;
case 13: card[i] = value[13]; break;
}
boolean isFull = true;
for(String s : card) {
if(s == null) {
isFull = false;
break;
}
}
}
} //"multiple markers in this line"
最佳答案
您错误地使用了||
if(inputSuit = 1 || 2 || 3 || 4 ){
这样做
if(inputSuit == 1 || inputSuit == 2 || inputSuit == 3 || inputSuit == 4 ){
||
用于进行 boolean 逻辑或,一般用法是
((Boolean Expression 1) || (Boolean Expression 2) || (Boolean Expression 3)...)
同样纠正这个问题
if(inputValue = 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 || 9 || 10 || 11 || 12 || 13){
关于java - 为什么我在 Eclipse 中收到这些错误?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20103424/