所以我试图将 ArrayList 传递给我的 main 方法,但 eclipse 告诉我我需要将 arraylist 更改为静态。我知道我做错了什么,但我无法弄清楚。
ArrayList<Patient> pList = Doctor.getPatientList();
这是我在主方法中进行的调用。
public class Doctor {
public ArrayList<Patient> patientList = new ArrayList<Patient>();
}
public void loadPatientData() {
BufferedReader read2 = null;
try {
read2 = new BufferedReader(new FileReader("data/patient_list.txt"));
String line;
while ((line = read2.readLine()) != null) {
line = read2.readLine();
if (line == null) {
break;
}
String[] lineValues = line.split(","); //split the string on this value into array
String firstName = lineValues[0];
String lastName = lineValues[1];
String address = lineValues[2];
String city = lineValues[3];
String state = lineValues[4];
String zip = lineValues[5];
String ssn = lineValues[6];
String genderNeedsConvert = lineValues[7];
String weightNeedsDouble = lineValues[8];
String heightNeedsDouble = lineValues[9];
String symptomsNotReady = lineValues[10]; // these need to be broken up further (using semicolons)
char gender = genderNeedsConvert.charAt(0);
double weight = Double.parseDouble(weightNeedsDouble);
double height = Double.parseDouble(heightNeedsDouble);
Patient patient = new Patient(firstName, lastName, address, city, state, zip, ssn, gender, weight, height, symptomsNotReady);
patientList.add(patient); // must be of patient type.
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
if (read2 != null) {
try {
read2.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
public ArrayList<Patient> getPatientList() {
return patientList;
}
这是我的 Doctor 类(class)的简化版本。
public class Patient {
private String patientID;
private String firstName;
private String lastName;
private String ssn;
private char gender;
private String address;
private String city;
private String state;
private String symptoms;
private String zip;
public ArrayList<Diagnosis> diagnoses = new ArrayList<Diagnosis>();
//private Diagnosis diagnoses = new Diagnosis(0, null);// new diagnoses called as Diagnoses datatype
public ArrayList<Medication> newMedication = new ArrayList<Medication>();
//private Medication newMedication = new Medication(0, null);// newMedication called as medication datatype
ArrayList<String> symptom = new ArrayList<String>();
ArrayList<String> symptomCompare = new ArrayList<String>();
private double weight;
private double height;
int k = 0;
public Patient(String firstName,String lastName,String address,String city, String state,String zip,String ssn,char gender,double weight,double height,String symptoms){
this.firstName = firstName;
this.lastName = lastName;
this.ssn = ssn;
this.gender = gender;
this.weight = weight;
this.height = height;
this.address = address;
this.city = city;
this.state = state;
this.symptoms = symptoms;
this.zip = zip;
this.patientID = ssn.replace("-", ""); // removes dashes from ssn and sets the value to patientID
this.patientID = this.patientID.replace(" ", ""); //removes spaces from patientID
this.patientID = this.patientID + this.firstName.substring(0, 1) + this.lastName.substring(0, 1);
}
及以上是缩短的患者类别。我已经坐在这里几个小时尝试不同的事情,但它一直告诉我将 getPatientList() 方法更改为静态。我做错了什么?
最佳答案
Doctor.getPatientList()
是调用静态方法的语法,因为 Doctor
是一个类名。
如果您想调用实例方法(并且 getPatientList()
当前是一个实例方法),您应该使用 Doctor
的实例来调用它:
Doctor doctor = new Doctor();
ArrayList<Patient> pList = doctor.getPatientList();
关于java - 静态建议。我究竟做错了什么?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27398329/