java - Java 中的 Ascii 表

Question

我在创建用于游戏的表格时遇到问题。它需要有

• 3 个人类字符@,
• 2 个怪物 #,
• 3 个宝箱*
• 和 4 个障碍O。

表格需要是 10 x 10 的正方形，并且间隙应该用 填充。 它应该看起来像这样:

   1 2 3 4 5 6 7 8 9 10
 1 . @ . * . . . . . .
 2 . . . . . # . . O .
 3 . . . . . . . . . .
 4 . . . . . . . . . .
 5 . . . # . . @ . . .
 6 . . O . . . . . . .
 7 . . . . O . . . O .
 8 . . . . . . * . . .
 9 . * . . . . . . . .
10 . . . . . . . @ . .

I also need to be able to move the chapters in the end. This is my currant code. But I can only get it so that the . and @ appear, otherwise I just get errors. Even when using else if:

package test;

import java.util.Scanner;


public class Test {

    public static void show(boolean[][] grid) {

        String s = "";

        for (boolean[] row : grid) {

            for (boolean col : row)

                if (col)

                    s += "@ ";

                else

                    s += ". ";

            s += "\n";

        }

        System.out.println(s);

    }

    public static boolean[][] gen() {

        boolean[][] grid = new boolean[10][10];

        for (int r = 0; r < 10; r++)

            for (int c = 0; c < 10; c++)

                if (Math.random() > 0.2)

                    grid[r][c] = true;

        return grid;

    }

    public static void main(String[] args) {

        boolean[][] world = gen();

        show(world);

        System.out.println();

        world = nextGen(world);

        show(world);

        Scanner s = new Scanner(System.in);

        while (s.nextLine().length() == 0) {

            System.out.println();

            world = nextGen(world);

            show(world);

        }

    }

    public static boolean[][] nextGen(boolean[][] world) {

        boolean[][] newWorld

        = new boolean[world.length][world[0].length];

        int num;

        for (int r = 0; r < world.length; r++) {

            for (int c = 0; c < world[0].length; c++) {

                num = numNeighbors(world, r, c);

                if (occupiedNext(num, world[r][c]))

                    newWorld[r][c] = true;

            }

        }

        return newWorld;

    }

    public static boolean occupiedNext(int numNeighbors, boolean occupied) {

        if (occupied && (numNeighbors == 2 || numNeighbors == 3))

            return true;

        else if (!occupied && numNeighbors == 3)

            return true;

        else

            return false;

    }

    private static int numNeighbors(boolean[][] world, int row, int col) {

        int num = world[row][col] ? -1 : 0;

        for (int r = row - 1; r <= row + 1; r++)

            for (int c = col - 1; c <= col + 1; c++)

                if (inbounds(world, r, c) && world[r][c])

                    num++;

        return num;

    }

    private static boolean inbounds(boolean[][] world, int r, int c) {

        return r >= 0 && r < world.length && c >= 0 &&

        c < world[0].length;

    }

}

有人知道如何帮助我输入所有符号吗？

Answer 1

您正在为网格使用 boolean 二维数组。所以每个条目只能有两个值。例如，如果将其切换为 int[][]，则可以为可能居住在该单元格中的不同类型的对象指定不同的值。举例来说:

1. 人类“@”
2. 怪物“#”
3. 宝箱“*”
4. 障碍物“O”

也许可以使用 0 = 未占用的“.”，因为整数无论如何都默认为零。