下面是我到目前为止的代码,它是我的计算机科学课上的计算器。我遇到的问题是在程序第二次运行时 System.out.print("你想执行计算吗?(y/n) ");运行两次而不是一次。我已经提交了该项目,但我想知道它为什么会这样做以及在我 future 的程序中如何修复它。我将在下面发布其余的代码。
感谢大家的帮助,我将获得的“A”归功于你们所有人。谢谢!
/**
* A calculator with multiple functions.
* @author ()
* @version (version 2.1)
*/
import java.io.*;
import java.util.Scanner;
public class Calc
{
public static void main(String args[])
{
Scanner reader = new Scanner(System.in);
String cont = "", funct = "";
double fnum = 0, snum = 0, answer = 0;
while(true)
{
System.out.print("Would you like to perform a calculation? (y/n) ");
cont = reader.nextLine();
if (cont.equalsIgnoreCase("y"))
{
System.out.println("What function would you like to do?");
System.out.println("+?");
System.out.println("-?");
System.out.println("*?");
System.out.println("/?");
funct = reader.nextLine();
if (funct.equals("+"))
{
System.out.println("Simple addition calculator");
System.out.println("Enter first num: ");
fnum = reader.nextDouble();
System.out.println("Enter second num: ");
snum = reader.nextDouble();
answer = fnum + snum;
System.out.println("Answer: " + answer);
System.out.println(" ");
}
if (funct.equals("-"))
{
System.out.println("Simple subtraction calculator");
System.out.println("Enter first num: ");
fnum = reader.nextDouble();
System.out.println("Enter second num: ");
snum = reader.nextDouble();
answer = fnum - snum;
System.out.println("Answer: " + answer);
System.out.println(" ");
}
if (funct.equals("*"))
{
System.out.println("Simple multiplication calculator");
System.out.println("Enter first num: ");
fnum = reader.nextDouble();
System.out.println("Enter second num: ");
snum = reader.nextDouble();
answer = fnum * snum;
System.out.println("Answer: " + answer);
System.out.println(" ");
}
if (funct.equals("/"))
{
System.out.println("Simple division calculator");
System.out.println("Enter first num: ");
fnum = reader.nextDouble();
System.out.println("Enter second num: ");
snum = reader.nextDouble();
answer = fnum / snum;
System.out.println("Answer: " + answer);
System.out.println(" ");
}
}
else if (cont.equalsIgnoreCase("n"))
{
break;
}
}
}
}
最佳答案
在循环内的所有函数条件中,您正在使用reader.nextDouble()。这只会读取输入的数字(例如“8”),而不读取用户在数字后输入的新行(回车)。 以下减号(-) 函数的代码不会打印两次“您想执行计算吗?(y/n)”,因为新行已被读取。这里使用reader.nextLine()而不是reader.nextDouble()。 reader.nextLine() 将读取整行,而不仅仅是数字。
if (funct.equals("-"))
{
System.out.println("Simple subtraction calculator");
System.out.println("Enter first num: ");
fnum = Double.parseDouble( reader.nextLine());
System.out.println("Enter second num: ");
snum = Double.parseDouble( reader.nextLine());
answer = fnum - snum;
System.out.println("Answer: " + answer);
System.out.println(" ");
}
关于java - 在 while 循环中停止重复的 Println,BlueJ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33447683/