我正在尝试使用 JPanel 制作康威生命游戏的一个版本。 但是，当我尝试迭代/推进我的游戏时，它不起作用。首先我看到一个空白的白色屏幕 5 秒钟，然后我看到一个没有变化的黑色方 block 。有谁知道解决办法吗？
这是我的代码:
package newJAVart;
import javax.swing.JFrame;
import javax.swing.JPanel;
import java.awt.*;
import java.awt.Dimension;
import java.awt.Graphics;
import java.lang.reflect.Array;
import java.util.Arrays;
import java.awt.*;
import java.applet.*;
import java.awt.Color;
import java.awt.Container;
import java.awt.Dimension;
import java.awt.Graphics;
import javax.swing.JFrame;
import javax.swing.JPanel;
public class ConwayGame {
static JPanel panel;
static JFrame frame;
static int[][] array = new int[40][40];
public static void main(String[] args) throws InterruptedException {
//Thread.sleep check if you can use it
array[5][5] = 1;
array[6][6] = 1;
//array[4][4] = 1;
array[5][6] = 1;
array[9][10] = 1;
// System.out.println(Arrays.deepToString(array));
//nextGeneration();
//System.out.println(Arrays.deepToString(array));
panel = new JPanel() {
@Override
public Dimension getPreferredSize() {
return new Dimension(400, 400);
}
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
int stop = 0;
while(stop<10){
//nextGeneration();
//array[34][34] = 1;
try {
nextGeneration();
System.out.println(Arrays.deepToString(array));
drawArray(array, g);
stop++;
array[5][6] = 0;
Thread.sleep(200);
g.dispose();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
};
frame = new JFrame();
frame.add(panel);
frame.pack();
frame.setVisible(true);
}
/*
* Creates the graphic for Conway's game of life.
*/
//this finds the states of all the squares next to the given one and handle edge cases
public static int nextTo(int a, int b){
int sum = 0;
// for(int i)
//if(a+1>array.length||)
//this will handle edge cases
int[] adjunc = new int[8];
if(a==0||b==0||a==array.length-1||b==array.length-1){
adjunc = new int[]{0,0,0,0,0,0,0,0};
}else{
/*
if(a==array.length-1|| b == array.length-1){
return nextTo(a-1,b-1);
}else if(a==0){
//adjunc = new int[]{array[a+1][b+1],array[a+1][b],array[a+1][b-1],array[a][b+1],
// array[array.length - 1 ][b-1],array[array.length -1 ][b],array[a-1][b+1],array[a][b-1]};
//return nextTo(a-1,b-1);
a =
}else if(b==0){
adjunc = new int[]{array[a+1][b+1],array[a+1][b],array[a+1][b-1],array[a][b+1],
array[a-1][b-1],array[a-1][b],array[a-1][b+1],array[a][b-1]};
}else{
*/
adjunc = new int[]{array[a+1][b+1],array[a+1][b],array[a+1][b-1],array[a][b+1],
array[a-1][b-1],array[a-1][b],array[a-1][b+1],array[a][b-1]};
}
//}
for(int check: adjunc){
if(check == 1){
sum = sum +1;
}
}
return sum ;
}
public static void nextGeneration(){
int[][] grid = new int[40][40];
for(int i=0;i<array.length-2;++i){
for(int j=0;j<array[0].length-2;++j){
//heres my error nexTo is being called on eveything including side elements
int stuff = nextTo(i,j);
if(array[i][j] ==1 && stuff < 2){
System.out.println("This is running");
//Any live cell with fewer than two live neighbors dies,as if caused by under-population
if(i==34){
System.out.println("This is number 34");
}
grid[i][j] = 0;
}else if(array[i][j]==1 && stuff>3){
System.out.println("This is running2");
grid[i][j] = 0;
}
else if(array[i][j] == 0 && stuff ==3){
System.out.println("This is running3");
grid[i][j] = 1;
}
}
}
array = grid;
}
/*
* else if(array[i][j]==1 && (stuff<4 || stuff >2)){
}
*
*/
//draws Array in JPanel
public static void drawArray(int[][] array, Graphics g) {
int BOX_DIM = 10;
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array[0].length; j++) {
g.drawRect(i * BOX_DIM, j * BOX_DIM, 10, 10);
if (array[i][j] == 0) {
g.setColor(Color.WHITE);
g.fillRect(i * BOX_DIM, j * BOX_DIM, 10, 10);
}
if (array[i][j] == 1) {
g.setColor(Color.BLACK);
g.fillRect(i * BOX_DIM, j * BOX_DIM, 10, 10);
}
}
}
}
}
最佳答案
所有的迭代、绘画和等待都发生在paintComponent中 - 因此阻止 UI实际显示它。您应该考虑一次进行一次迭代的方法，并让paintComponent绘制当前迭代，同时外部线程执行等待和游戏处理。
基本上，从paintComponent中删除除drawArray()之外的所有内容，并在其他地方执行其余操作 - 一旦完成一次迭代，就会在EDT中触发重新绘制。
关于java - 康威生命游戏迭代不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/34073848/