java - 2 个扫描仪但有一个 onActivityResult？

Question

我正在 Android Studio 中开发移动应用程序，并且有 2 个按钮。 每个按钮都将使用 Zxing 库启动条形码/QR 扫描。

我遇到的问题是我将第一次扫描的结果分配给按钮文本，并且工作正常。

但是，当将第二次扫描的结果分配给其按钮时，它不起作用，因为只有一个 onActivityResult？

我知道，如果我复制并粘贴代码并尝试覆盖 onActivityResult2，系统将忽略它，因为系统无法识别它。

但是，我该如何解决这个问题呢？

这是我的 onActivityResult 和 onActivityResult2 代码，只是为了展示我想要实现的目标:

Activity 结果:

工作代码:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    IntentResult result = IntentIntegrator.parseActivityResult(requestCode, resultCode, data);

    if (result != null) {
        //if qrcode has nothing in it
        if (result.getContents() == null) {
            Toast.makeText(this, "Result Not Found", Toast.LENGTH_LONG).show();
        } else {
            //if qr contains data
            try {
                //converting the data to json
                JSONObject obj = new JSONObject(result.getContents());

            } catch (JSONException e) {
                e.printStackTrace();
                if (buttonId == R.id.buttonScan) {
                    machineType = result.getContents();
                    scanBarcode.setText("Machine Type: " + machineType);
                } else if (buttonId == R.id.buttonScan2) {
                    workOrderNumber = result.getContents();
                    scanWorkOrder.setText("Work Order Number: " + workOrderNumber);
                }
                else if (buttonId == 0) {
                    ???
                }

            }
        }
    } else {
        super.onActivityResult(requestCode, resultCode, data);
    }
}

调用库的按钮:

private IntentIntegrator qrScan;
private IntentIntegrator qrScan2;

int buttonId = 0; //THIS IS GLOBAL

 //Initialise Buttons
    scanBarcode = findViewById(R.id.buttonScan);
    scanWorkOrder = findViewById(R.id.buttonScan2);
    submit = findViewById(R.id.buttonSubmit);

    sharedPreferences = getSharedPreferences(MyPREFERENCES, Context.MODE_PRIVATE);

    //Initialize Scanners
    qrScan = new IntentIntegrator(this);


    scanBarcode.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
            qrScan.initiateScan();
            buttonId = R.id.buttonScan;
        }
    });

    scanWorkOrder.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
            qrScan.initiateScan();
            buttonId = R.id.buttonScan2;

        }
    });

Answer 1

在遵循重载规则时，您不能拥有两个完全相同的方法，因此

对于两个请求，您可以有两个不同的requestCode，然后使用if语句来识别您的请求类型或按钮点击响应

startActivityForResult (intent, 100); // 100 for button 1
startActivityForResult (intent, 101); // 101 for button 2

在ActivityResult

中

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    IntentResult result = IntentIntegrator.parseActivityResult(requestCode, resultCode, data);
    if (result != null) {
        //if qrcode has nothing in it
        if (result.getContents() == null) {
            Toast.makeText(this, "Result Not Found", Toast.LENGTH_LONG).show();
        } else {
            //if qr contains data
            try {
                //converting the data to json
                JSONObject obj = new JSONObject(result.getContents());

            } catch (JSONException e) {
                e.printStackTrace();

                workOrderNumber = result.getContents();
                if(requestCode == 100)
                    scanBarcode.setText("Machine Type: " + machineType);
                else if(requestCode == 101)
                    scanWorkOrder.setText("Work Order Number: " + workOrderNumber);                 
             }
        }
    } else {
        super.onActivityResult(requestCode, resultCode, data);
    }
}