java - 使用 JAVA 将字符串拆分为多个部分并存储为 CSV

Question

我有不同格式的数据。我希望首先从输入字符串中提取数量，然后提取单位，其余文本应视为项目。

代码.java

  public String itemsProcesing(List<String> items) throws IOException {
        List<String> list = items;
        List<String> unitList = Arrays.asList("g", "tbsp", "cm", "kg"");
        List<String> quantityList = Arrays.asList("Full", "Quarter", "Half", "3 Quarter", "1", "2", "3", "4", "5", "6", "7", "8", "9", "0");

        for (String s : list) {
            String[] strArr = s.split(" ");
            if (strArr.length == 2) {
                String newStr = rewriteString(strArr, quantityList);
                strArr = newStr.split(" ");
            }
            String[] itemLine = new String[3];
            for (int i = 0; i < strArr.length; i++) {
                String str = strArr[i];
                int index = findValueLocation(str, unitList);
                itemLine[index] = str;
            }
            String line = createLineForCSV(itemLine);
            writeToFile(line);

        }


        return "done";
    }

    private static int findValueLocation(String str, List<String> unitList) {
         boolean b = Pattern.matches("\\d{1,3}|\\d/\\d|\\d/\\d[*]\\d|\\d{1,3}[*]\\d{1,3}|\\d{1,3}[*]\\d{1,3}|\\d{1,3}[-]\\d{1,3}|\\d{1,3} [-] \\d{1,3}|\\d.\\d|\\\\d{1,3} - \\\\d{1,3}| \\\\d{1,3} - \\\\d{1,3}| \\\\d{1,3}-\\\\d{1,3}", str);
        if (b) {
            return 0;
        }

        for (String unit : unitList) {
            if (unit.equals(str)) {
                return 1;
            }
        }
        return 2;
    }

    private static String createLineForCSV(String[] itemLine) {
        StringBuilder sb = new StringBuilder();
        sb.append(itemLine[0]).append(",");
        sb.append(itemLine[1]).append(",");
        sb.append(itemLine[2]);
        return sb.toString();
    }

    private static void writeToFile(String line) throws IOException {
        BufferedWriter writer = new BufferedWriter(new FileWriter("csv_file.csv", true));
        writer.write(line);
        writer.newLine();
        writer.close();
    }

    private static String rewriteString(String[] arr, List<String> quantityList) {
        String strOne = arr[0];
        String strTwo = arr[1];
        String newStr = "";
        for (String quantity : quantityList) {
            if (strOne.contains(quantity)) {
                // 8g carrots becomes "8 g carrots"
                newStr = quantity + " " + strOne.substring(quantity.length()) + " " + strTwo;
                break;
            } else if (strTwo.contains(quantity)) {
                newStr = quantity + " " + strTwo.substring(quantity.length()) + " " + strOne;
                break;
            }
        }
        return newStr;
    }

Input data 1-2 tbsp soya sauce

Ouptut : 1-2,tbsp,sauce

Required Output: 1-2,tbsp,soya sauce

我如何获得所需的结果。

Answer 1

我认为仅构建一个详尽的测量单位列表并沿其拆分字符串就足够了。那么你就不需要解析金额了。

类似这样的事情:

Pattern p=Pattern.compile("(.*?)\\s*(tbsp|k?g|cup|c?m)\\s*(.*)");
List<String> tests=Arrays.asList(
  "16g salt",
  "1 kg apple",
  "1 1/2 tbsp sugar");
for(String s:tests){
  Matcher m=p.matcher(s);
  if(m.matches())
    System.out.println(Arrays.asList(m.group(1),m.group(2),m.group(3)));
}

输出(来自 https://ideone.com/9kbozK ):

[16, g, salt]
[1, kg, apple]
[1 1/2, tbsp, sugar]

在现实生活中，应该有一个 else 分支来捕获输入中可能存在的错误(或无法识别的单元)。