我正在做一个 TicTacToe 程序，唯一缺少的部分是让用户选择是否退出游戏或重玩。我找不到“返回”游戏的方法。
import java.io.*;
public class Expierment
{
static char c1 [] = new char[10];
static char c2 [] = new char[10];
static char c3 [] = new char[10];
static char p1;
static char p2;
static boolean gameOver = false;
public static void main(String args[])
{
int counter = 0;
int p1Wins = 0;
int p2Wins = 0;
int r1 = 0;
int r2 = 0;
int r3 = 0;
int r4 = 0;
int r5 = 0;
int r6 = 0;
int r7 = 0;
int r8 = 0;
int r9 = 0;
int pick1 = 0;
int pick2 = 0;
int pick3 = 0;
int pick4 = 0;
int pick5 = 0;
int pick6 = 0;
int pick7 = 0;
int pick8 = 0;
int pick9 = 0;
char turn = 'X';
int choice = menu();
switch(choice)
{
case 1:
System.out.println("The game is called 'Tic-Tac-Toe', you should have known it. If you don't, search it.") ;
case 2:
gameOver = false;
break;
case 3:
System.out.println("\nSee you next time !!");
return;
default:
System.out.println("\nYou hit the wrong key......\n");
return;
}//end of switch
System.out.println("\nPlayer 1 initials ?");
String n1 = GCS();
p1 = n1.charAt(0);
System.out.println("\nPlayer 2 initials ?");
String n2 = GCS();
p2 = n2.charAt(0);
c1[2]='1';
c2[2]='2';
c3[2]='3';
c1[1]='4';
c2[1]='5';
c3[1]='6';
c1[0]='7';
c2[0]='8';
c3[0]='9';
printBoard ();
while(gameOver!=true)
{
System.out.println("Which spot ?");
int pick = Integer. parseInt(GCS());
switch (pick)
{
case 1:
if (r1<1)
{
c1[2] = turn;
r1++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 2:
if (r2<1)
{
c2[2] = turn;
r2++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 3:
if (r3<1)
{
c3[2] = turn;
r3++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 4:
if (r4<1)
{
c1[1] = turn;
r4++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 5:
if (r5<1)
{
c2[1] = turn;
r5++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 6:
if (r6<1)
{
c3[1] = turn;
r6++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 7:
if (r7<1)
{
c1[0] = turn;
r7++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 8:
if (r8<1)
{
c2[0] = turn;
r8++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
case 9:
if (r9<1)
{
c3[0] = turn;
r9++;
}
else
{
System.out.println("That column is full, pick another.\n");
continue;
}
break;
default:
System.out.println("Seriously?! Pick a possible spot.\n");
continue;
}//end of switch
if (turn=='X') turn = 'O';
else turn = 'X';
printBoard();
if (checkWinner())
{
while(gameOver==true)
{
int Echoice = EGM();
switch(Echoice)
{
case 1:
System.out.println("The game is called 'Tic-Tac-Toe', you should have known it. If you don't, search it.") ;
case 2:
gameOver = false;
menu();
break;
case 3:
System.out.println("\nSee you next time !!");
return;
default:
System.out.println("\nYou hit the wrong key......\n");
return;
}//end of switch
}//end of while true
return;
}
counter ++;
if (counter==9)
{
System.out.println("\n\nYou tied.\n");
return;
}
}//end of while not true
}//end of main
public static boolean checkWinner()
{
for (int k=0; k<2; k++)
{
if ((c1[k]!=' ')&&(c1[k]==c2[k])&&(c1[k]==c3[k]))
{
System.out.println("\nYo " + c1[k] + " is the winner!\n");
gameOver=true;
return true;
}//checks column 1-3 horizontally
}//end of horizontal check
for (int m=0; m<2; m++)
{
if((c1[m]!=' ')&&(c1[m]==c1[m+1])&&(c1[m+1]==c1[m+2])&&(c1[m]==c1[m+2]))
{
System.out.println("\nYo " + c1[m] + " is the winner!\n");
gameOver=true;
return true;
}//checks column 1 vertically
if((c2[m]!=' ')&&(c2[m]==c2[m+1])&&(c2[m+1]==c2[m+2])&&(c2[m]==c2[m+2]))
{
System.out.println("\nYo " + c2[m] + " is the winner!\n");
gameOver=true;
return true;
}//checks column 2 vertically
if((c3[m]!=' ')&&(c3[m]==c3[m+1])&&(c3[m+1]==c3[m+2])&&(c3[m]==c1[m+2]))
{
System.out.println("\nYo " + c3[m] + " is the winner!\n");
gameOver=true;
return true;
}//checks column 3 vertically
if ((c1[m]!=' ')&&(c1[m]==c2[m+1])&&(c1[m]==c3[m+2]))
{
System.out.println("\nYo " + c1[m] + " is the winner!\n");
gameOver=true;
return true;
}//checks upward diagonal
if ((c3[m]!=' ')&&(c3[m]==c2[m+1])&&(c3[m]==c1[m+2]))
{
System.out.println("\nYo " + c1[m] + " is the winner!\n");
gameOver=true;
return true;
}
}//end of vertical check
return false;
}//end of checkWinner
public static void printBoard()
{
System.out.println("_______");
for (int j = 2; j > -1; j--)
{
System.out.println("|" + c1[j] + "|" + c2[j] + "|" + c3[j] + "|");
System.out.println("-------");
}
}//end of printBoard
public static int menu()
{
System.out.println("Tic-Tac-Toe ~ Main Menu\n\n1. Instructions\n2. Play a 1 player game"+"\n3. Exit\n");
int selection = Integer.parseInt(GCS());
return selection;
}//end of menu
public static int EGM()
{
System.out.println("Tic-Tac-Toe ~ End of Game Menu\n\n1. Instructions\n2. Play again"+"\n3. Exit\n");
int Eselection = Integer.parseInt(GCS());
return Eselection;
}
public static String GCS()
{
int noMoreInput=-1;
char enterKeyHit='\n';
int InputChar;
StringBuffer InputBuffer = new StringBuffer(100);
try
{
InputChar=System.in.read();
while(InputChar != noMoreInput)
{
if((char)InputChar !=enterKeyHit)
{
InputBuffer.append((char)InputChar);
}
else
{
InputBuffer.setLength(InputBuffer.length()-1);
break;
}
InputChar=System.in.read();
}
}
catch (IOException IOX)
{
System.err.println(IOX);
}
return InputBuffer.toString();
}//end of GCS
}//end of public class
最佳答案
您确实应该从 main 函数中获取一些代码。
具体来说，我会将整个游戏循环放在一个单独的函数中，可能称为 playGame()，其中包含玩游戏、检查获胜者等的逻辑，并且返回获胜者或仅打印获胜者并返回 void。
然后主函数可以在循环中调用 playGame()，并在循环结束时询问用户是否想再次玩。
一般来说，您希望每个函数执行一个逻辑任务。您已经很好地移出了 checkWinner，现在对其他一些代码执行相同的操作。
如果您需要有关“询问用户是否再次玩游戏”的帮助，请发表评论，我将进行编辑以解决该问题。
关于java - 如何返回游戏？完成游戏后，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/4787892/