java - 如何在不绕过另一代码块的情况下执行一段代码？ java

Question

标题可能没有提供太多信息。但事情就是这样。

我希望用户在第二次经过那里时执行代码。我所做的是制作一个 if 语句，但现在我注意到，有了这个，其余的就没有被执行。

Scanner input = new Scanner(System.in);
Random dice = new Random();
int counter = 1;
boolean playing = true;
boolean firstTimmer = true;
boolean got = true;

System.out.println("Welcome to numberMind! From 0 to x, you'll try to guess the random number!");
System.out.println("To quit, guess \"-1\".");
System.out.print("Insert x: ");
int x = 1+input.nextInt();
int objective = dice.nextInt(x);
System.out.print("Ok, I'm ready! What's your first guess? ");
int guess = input.nextInt();


while (playing){
    if (guess == -1){
        playing = false;
        break;
    }else if (!firstTimmer){
        got = true;
        System.out.print("Do you want to change the number range? Yes(1) No(2)");
        guess = input.nextInt();
        if (guess == 1){
            System.out.print("Insert the new x: ");
            x = 1+input.nextInt();
        }else if(guess == 2){
            System.out.println("Let's go then!");
        }else{
            System.out.print("I didn't ask for that number did I? x won't change.");
        }
    }else{
        while(got){
            if (objective == guess){
                firstTimmer = false;
                System.out.println("You guessed it in "+counter+" times!");
                counter = 1;
                System.out.print("Do you want to paly again? Yes(1) No(2) ");
                guess = input.nextInt();
                if (guess == 1){
                    System.out.println("Great! Here we go...");
                    got = false;
                    break;
                }else if (guess == 2){
                    System.out.print("Thanks for playing!");
                    got = false;
                    playing = false;
                }else{
                    System.out.println("We didn't ask for that. NOW YOU PLAY SOME MORE!");
                    got = false;
                    break;
                }
                break;
            }else if (guess == -1){
                System.out.println("You quited :(");
                break;
            }else if (guess == -2){
                System.out.println("The correct answer is "+ objective);
            }else if (counter >= 5 && (counter -5) % 3 == 0 ){
                if (objective % 2 == 0){
                    System.out.println("The number is pair.");
                }else{
            System.out.println("The number is odd.");
                }
            }
            System.out.println("You have tryed " + counter++ + " times.");
            System.out.print("What's your guess? ");
            guess = input.nextInt();
        }
    }
}

我想要运行的代码位于最后一个 else 之后。我没有看到任何可以解决它的东西。谢谢

Answer 1

我们首先要问自己else何时会实现:当guess != -1且firstTimmer == true时。您无需设置 firstTimmer，它需要设置为 true 才能通过 else block 。您还需要删除 else if 中的 break，否则它在下一次迭代中永远不会到达 else。

此外，在 if 语句中同时使用 playing = false 和 break 是多余的。两者都会分别做同样的事情。

while (playing){
    if (guess == -1){
        playing = false;
        break;
    }else if (!firstTimmer){
        got = true;
        System.out.print("Do you want to change the number range? Yes(1) No(2)");
        guess = input.nextInt();
        if (guess == 1){
            System.out.print("Insert the new x: ");
            x = 1+input.nextInt();
        }else if(guess == 2){
            System.out.println("Let's go then!");
        }else{
            System.out.print("I didn't ask for that number, x won't change.");
        }
        firstTimmer = true;
        //break;
    }else{