我使用的是 urlrewritefilter 4.0.3,我总是遇到 stackoverflow 错误。这是我的配置:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext*.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>UrlRewriteFilter</filter-name>
<filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
<init-param>
<param-name>statusEnabled</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>UrlRewriteFilter</filter-name>
<url-pattern>/annotation/*</url-pattern>
<dispatcher>REQUEST</dispatcher>
<dispatcher>FORWARD</dispatcher>
</filter-mapping>
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>*.action</url-pattern>
<dispatcher>REQUEST</dispatcher>
<dispatcher>FORWARD</dispatcher>
<dispatcher>INCLUDE</dispatcher>
</filter-mapping>
这是我的网址重写模式:
<rule>
<note>
Redirect find annotation by object id.
</note>
<from>/annotation/([a-z0-9]+)</from>
<to type="forward">/annotation/getAnnotationByObjectID.action?oid=$1</to>
</rule>
一旦我运行它,我总是得到:
javax.servlet.ServletException: Filter execution threw an exception org.tuckey.web.filters.urlrewrite.NormalRewrittenUrl.doRewrite(NormalRewrittenUrl.java:213) org.tuckey.web.filters.urlrewrite.RuleChain.handleRewrite(RuleChain.java:171) org.tuckey.web.filters.urlrewrite.RuleChain.doRules(RuleChain.java:145) ... root cause java.lang.StackOverflowError javax.servlet.ServletRequestWrapper.isAsyncStarted(ServletRequestWrapper.java:403) javax.servlet.ServletRequestWrapper.isAsyncStarted(ServletRequestWrapper.java:403) javax.servlet.ServletRequestWrapper.isAsyncStarted(ServletRequestWrapper.java:403) javax.servlet.ServletRequestWrapper.isAsyncStarted(ServletRequestWrapper.java:403)
我对此很生气。如果您知道是怎么回事,请帮助我。多谢。
最佳答案
<from>
中的正则表达式规则没有锚定。显然,规则正在寻找 URL 内的任何匹配项,因此如果它们未锚定(开头有 ^
,结尾有 $
),它们将匹配 URL 内的任何内容。
因此,您的目标网址 /annotation/getAnnotationByObjectID.action?oid=$1
实际上与您的 from
匹配规则(/annotation/get
部分执行)。因此它会在无限循环中一遍又一遍地运行相同的规则。
解决方案应该是锚定规则:
<from>^/annotation/([a-z0-9]+)$</from>
关于java - 使用 SSH2 和 URLrewrite 并出现 stackoverflow 错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29287637/