java - 检查文本是否有多个链接

Question

我想检查文本是否有多个链接 因此，我从以下代码开始:

private static void twoOrMorelinks(String commentstr){
     String urlPattern = "^.*((?:http|https):\\/\\/\\S+){1,}.*((?:http|https):\\/\\/\\S+){1,}.*$";
     Pattern p = Pattern.compile(urlPattern,Pattern.CASE_INSENSITIVE);
        Matcher m = p.matcher(commentstr);
        if (m.find()) {
            System.out.println("yes");
        }
}

但是上面的代码不是很专业，我正在寻找如下内容:

private static void twoOrMorelinks(String commentstr){
     String urlPattern = "^.*((?:http|https):\\/\\/\\S+){2,}.*$";
     Pattern p = Pattern.compile(urlPattern,Pattern.CASE_INSENSITIVE);
        Matcher m = p.matcher(commentstr);
        if (m.find()) {
            System.out.println("yes");
        }
}

但是此代码不起作用，例如我希望代码显示与以下文本的匹配，但事实并非如此:

They say 2's company watch live on...? http://www.le testin this code  http://www.lexilogos.com

有什么想法吗？

Answer 1

只需使用它来计算您拥有的链接数量:

private static int countLinks(String str) {
    int total = 0;
    Pattern p = Pattern.compile("(?:http|https):\\/\\/");
    Matcher m = p.matcher(str);
    while (m.find()) {
        total++;
    }
    return total;
}

然后

boolean hasMoreThanTwo = countLinks("They say 2's company watch live on...? http://www.le testin this code  http://www.lexilogos.com") >= 2;

如果您只想知道是否有两个或更多，请在找到两个后退出。