我正在构建的应用程序中有以下界面:
package sistemata;
public interface PaymentgatewayAdapter
{
public String postPayment(String a);
}
下面的类实现了它:
public class PaypalAdapter implements PaymentgatewayAdapter
{
public String postPayment(String a)
{
String payAmount;
String transactionOutcome;
String response;
payAmount = a;
Paypal_sim systemGN = new Paypal_sim();
System.out.println("v adaptera" + a);
//Simulerar att data skickas till externa systemet
response = systemGN.transferSaleData(payAmount);
if (response == "OK")
{
transactionOutcome = "OK";
}
else
{
transactionOutcome = "Invalid data sent to MasterCard.";
}
return transactionOutcome;
//------------------------------
}
}
还有第二个几乎相同的类,称为 Payson,但未使用。
此接口(interface)是 ServicesFactory
的一部分:
package sistemata;
public class ServicesFactory
{
private static ServicesFactory instance;
private PaymentgatewayAdapter paymentAdapter;
private String className2;
public static synchronized ServicesFactory getInstance()
{
instance = new ServicesFactory();
return instance;
}
public PaymentgatewayAdapter getPaymentAdapter(String className2)
{
this.className2 = className2;
if (paymentAdapter == null)
{
try
{
paymentAdapter = (PaymentgatewayAdapter)
Class.forName(className2).newInstance();
}
catch (Exception e)
{
System.out.println("ERROR: Cannot instantiate: " +
className2 + ".");
e.printStackTrace();
System.exit(1);
}
}
return paymentAdapter;
}
}
在Account
类中调用getPaymentAdapter
方法,如下所示:
else if (paymentMethod == 0)
{
System.out.println("The payment method is PayPal INC");
String className = "PaypalAdapter";
paymentAdapter = ServicesFactory.getInstance().getPaymentAdapter(className);
}
每当我打电话时:
paymentAdapter = ServicesFactory.getInstance().getPaymentAdapter(className);
我收到 System.out.println("ERROR: Cannot instantiate:.
) 中引发的错误
无论我尝试什么,我都无法解决这个问题,也找不到解决方案。我将感谢您对这段代码的帮助,甚至是硬编码的建议。
java.lang.ClassNotFoundException: PaymentgatewayAdapter
at java.net.URLClassLoader$1.run(Unknown Source)
at java.net.URLClassLoader$1.run(Unknown Source)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(Unknown Source)
at java.lang.ClassLoader.loadClass(Unknown Source)
at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
at java.lang.ClassLoader.loadClass(Unknown Source)
at java.lang.Class.forName0(Native Method)
at java.lang.Class.forName(Unknown Source)
at sistemata.ServicesFactory.getPaymentAdapter(ServicesFactory.java:26)
at sistemata.Account.makePayment(Account.java:56)
at sistemata.MainSystem.main(MainSystem.java:71)
最佳答案
您是否忘记了这一行中的包名称?
String className = "PaypalAdapter";
应该是
String className = "sistemata.x.y.z.PaypalAdapter";
关于java - 无法从接口(interface)实例化类,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20004851/