我需要将 03/03/2015 转换为 3/3/2015。
这是我的代码:
public class getCorrectDates {
public static void main(String[] args) throws ParseException {
List<String> dates = getCorrectDates.getDates("3/2/2014", "03/03/2015");
System.out.println(dates);
}
public static List getDates(String dateStart, String dateEnd) throws ParseException {
List<Date> dates = new ArrayList<Date>();
List<String> formattedDates = new ArrayList<String>();
DateFormat formatter;
formatter = new SimpleDateFormat("MM/dd/yyyy");
Date startDate = (Date) formatter.parse(dateStart);
Date endDate = (Date) formatter.parse(dateEnd);
long interval = 24 * 1000 * 60 * 60; // 1 hour in millis
long endTime = endDate.getTime(); // create your endtime here, possibly using Calendar or Date
long curTime = startDate.getTime();
while (curTime <= endTime) {
dates.add(new Date(curTime));
curTime += interval;
}
for (int i = 0; i < dates.size(); i++) {
Date lDate = (Date) dates.get(i);
String ds = formatter.format(lDate);
formattedDates.add(ds);
System.out.println(ds);
}
return formattedDates;
}
}
输出:
02/28/2015 03/01/2015 03/02/2015 03/03/2015
我需要:
2/28/2015 3/1/2015 3/2/2015 3/3/2015
必须有一种方法可以获取数组中不带零的日期 在日期和月份中。我怎样才能做到这一点？
最佳答案
满足以下条件就足够了:
new SimpleDateFormat("M/d/YYYY");
引自java docs :
Number: For formatting, the number of pattern letters is the minimum number of digits, and shorter numbers are zero-padded to this amount. For parsing, the number of pattern letters is ignored unless it's needed to separate two adjacent fields.
关于java - 将 03/03/2015 转换为 3/3/2015 的简单快速方法，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/29062974/